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Top Forums Programming Java not getting in expected way Post 303017948 by jim mcnamara on Friday 25th of May 2018 09:37:28 AM
Old 05-25-2018
Hint: Your variable names made it hard for me to read your code. Variable names that indicate what they are -- really help. a,b,c,d,e do not convey much.

Code:
b.write(c,1,4);

This creates what you see in the file. "\n" works to solve your problem - watch out for windows OS.

So you need another call to write to c with one character, "\n".

Here is a lot more advanced discussion - note that java versions have different limitation on the use of writing to numbered file descriptors - depends on version and OS.
Using a numbered file descriptor from Java - Stack Overflow
 

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serialver(1)						      General Commands Manual						      serialver(1)

NAME
serialver - serial version command SYNOPSIS
serialver [ options ] [ classnames ] options Command-line options, as specified in this document. classnames One or more class names. DESCRIPTION
serialver returns the serialVersionUID for one or more classes in a form suitable for copying into an evolving class. When invoked with no arguments, it prints a usage line. OPTIONS
-classpath <directories and zip/jar files separated by:> Set search path for application classes and resources. -show Displays a simple user interface. Enter the full class name and press either the Enter key or the Show button to display the serialVersionUID. -Joption Pass option to the Java virtual machine, where option is one of the options described on the man page for the java applica- tion launcher, java(1). For example, -J-Xms48m sets the startup memory to 48 megabytes. It is a common convention for -J to pass options to the underlying virtual machine. SEE ALSO
See (or search java.sun.com) for the following: java.io.ObjectStreamClass @ http://java.sun.com/j2se/1.5/docs/api/java/io/ObjectStreamClass.html 24 June 2004 serialver(1)
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