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Top Forums Shell Programming and Scripting Grep a pattern in a key position a file Post 303017747 by Scrutinizer on Monday 21st of May 2018 04:01:25 PM
Old 05-21-2018
Try introducing an extra column 1, that contains the number of words in column 3, then sorting on that column and then removing the extra column, for example:
Code:
awk -F', *' 'NR>1 && NF{print split($3,F," "), $0}' OFS='\t' t22 | sort -k1,1n | cut -f2-

NR>1 && NF skips the header and the empty line and split($3,F," ") produces the number of words in column 3

Last edited by Scrutinizer; 05-21-2018 at 05:08 PM..
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COMM(1) 						    BSD General Commands Manual 						   COMM(1)

NAME
comm -- select or reject lines common to two files SYNOPSIS
comm [-123f] file1 file2 DESCRIPTION
The comm utility reads file1 and file2, which should be sorted lexically, and produces three text columns as output: lines only in file1; lines only in file2; and lines in both files. The filename ``-'' means the standard input. The following options are available: -1 Suppress printing of column 1. -2 Suppress printing of column 2. -3 Suppress printing of column 3. -f Fold case in line comparisons. Each column will have a number of tab characters prepended to it equal to the number of lower numbered columns that are being printed. For example, if column number two is being suppressed, lines printed in column number one will not have any tabs preceding them, and lines printed in column number three will have one. comm assumes that the files are lexically sorted; all characters participate in line comparisons. EXIT STATUS
comm exits 0 on success, >0 if an error occurred. SEE ALSO
cmp(1), diff(1), sort(1), uniq(1) STANDARDS
The comm utility conforms to IEEE Std 1003.2-1992 (``POSIX.2''). BSD
June 6, 1993 BSD
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