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Top Forums Shell Programming and Scripting Taking out part of a string by matching a pattern Post 303016439 by durden_tyler on Thursday 26th of April 2018 07:52:56 PM
Old 04-26-2018
Code:
$ 
$ echo PO_CREATE12457888888888889SK1234567878744551111111111SK89456321145789955455555SK8888888815788852222 | perl -lne 'while (/(SK.{8})/g){print $1}'
SK12345678
SK89456321
SK88888888
$ 
$

 

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GEOIP_REGION_NAME_BY_CODE(3)						 1					      GEOIP_REGION_NAME_BY_CODE(3)

geoip_region_name_by_code - Returns the region name for some country and region code combo

SYNOPSIS
string geoip_region_name_by_code (string $country_code, string $region_code) DESCRIPTION
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Returns the region name on success, or FALSE if the country and region code combo cannot be found. EXAMPLES
Example #1 A geoip_region_name_by_code(3) example using region code for US/Canada This will print the region name for country CA (Canada), region QC (Quebec). <?php $region = geoip_region_name_by_code('CA', 'QC'); if ($region) { echo 'Region name for CA/QC is: ' . $region; } ?> The above example will output: Region name for CA/QC is: Quebec Example #2 A geoip_region_name_by_code(3) example using FIPS codes This will print the region name for country JP (Japan), region 01. <?php $region = geoip_region_name_by_code('JP', '01'); if ($region) { echo 'Region name for JP/01 is: ' . $region; } ?> The above example will output: Region name for JP/01 is: Aichi PHP Documentation Group GEOIP_REGION_NAME_BY_CODE(3)
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