Hi,
I have a date input in MMDDYYYY format..
I have to give the day (whether that DD is sunday/monday...)
Is there any command for it...
Or do I have to write a script for that...
Thanks in Advance
Yeheya (1 Reply)
Hi,
I have a date field which is a variable field being passed to the script from outside.
I need to know how i can add 1 day to it.
I have seen example of date subtraction but while adding each time date reaches 31 or 30 i have to put if else condition.
Or for leap year also.
Kindly let... (4 Replies)
Hi, I have been trying just about every unix command to come up with yesterday's date (today's date - 1). I have seen all of the help on this forum, and none of it seems to work for me here. We are using Sun Solaris 9 Unix. I am using this script to create a .txt file with ftp commands that I will... (2 Replies)
i would need some help in setting the value of a variable (TIME_NOW) depending on the time of the day ...e.g.
if today's date is 12th April 2009 and if the current time is between midnight and 16:59:59 hrs then the TIME_NOW should be yesterday's date i.e. TIME_NOW=11
else if the current time... (3 Replies)
It's easy as pie to get the date minus one day on opensolaris:
date -d "-1 day" +"%Y%m%d"run this command on our crappy Solaris 10 machines however (which I'm guessing doesn't have GNU date running on it) and you get:
date: illegal option -- d
date: illegal option -- 1
date: illegal option --... (5 Replies)
Hi guys,
I had a scenario...
1. I had to get the previous days date in yyyymmdd format
2. i had to create a file with Date inthe format yyyymmdd.txt format
both are different
thanks guys in advance.. (4 Replies)
I need to get the next day's date of the user entered date
for example:
Enter date (yyyy/mm/yy):
2013/10/08I need to get the next day's date of the user entered date
Desired Output:
2013/10/09Though there are ways to achieve this is Linux or Unix environment (date command) ,I need to... (1 Reply)
I Have text like
XXX_20190908.csv.gz need to replace Only date in this format with current date every day
Thanks! (1 Reply)
Discussion started by: yamasani1991
1 Replies
LEARN ABOUT PHP
intlcalendar.setfirstdayofweek
INTLCALENDAR.SETFIRSTDAYOFWEEK(3) 1 INTLCALENDAR.SETFIRSTDAYOFWEEK(3)IntlCalendar::setFirstDayOfWeek - Set the day on which the week is deemed to start
Object oriented style
SYNOPSIS
public bool IntlCalendar::setFirstDayOfWeek (int $dayOfWeek)
DESCRIPTION
Procedural style
bool intlcal_set_first_day_of_week (IntlCalendar $cal, int $dayOfWeek)
Defines the day of week deemed to start the week. This affects the behavior of fields that depend on the concept of week start and end
such as IntlCalendar::FIELD_WEEK_OF_YEAR and IntlCalendar::FIELD_YEAR_WOY.
PARAMETERS
o $cal
- The IntlCalendar resource.
o $dayOfWeek
- One of the constants IntlCalendar::DOW_SUNDAY, IntlCalendar::DOW_MONDAY, , IntlCalendar::DOW_SATURDAY.
RETURN VALUES
Returns TRUE on success. Failure can only happen due to invalid parameters.
EXAMPLES
Example #1
IntlCalendar.setFirstDayOfWeek(3)
<?php
ini_set('date.timezone', 'Europe/Lisbon');
ini_set('intl.default_locale', 'es_ES');
$cal = IntlCalendar::createInstance();
$cal->set(2013, 5 /* June */, 30); // A Sunday
var_dump($cal->getFirstDayOfWeek()); // 2 (Monday)
echo IntlDateFormatter::formatObject($cal, <<<EOD
week of month : 'W'
week of year : 'ww
EOD
), "
";
$cal->setFirstDayOfWeek(IntlCalendar::DOW_SUNDAY);
echo IntlDateFormatter::formatObject($cal, <<<EOD
week of month : 'W'
week of year : 'ww
EOD
), "
";
The above example will output:
int(2)
local day of week: 7
week of month : 4
week of year : 26
local day of week: 1
week of month : 5
week of year : 27
PHP Documentation Group INTLCALENDAR.SETFIRSTDAYOFWEEK(3)