This bash-only script works with bash 3 on Solaris and bash 4 on Ubuntu.
To use it call it with yyyymmdd date strings as arguments.
The function zeller uses the Zeller algorithm to find the day of week from the given year/month/day. Result: 0 for a Sunday through to 6 for a Saturday.
Andrew
good idea, but...somehow the zeller function doesn't work correctly:
I would like to know how I could get a yesterday date in yyyymmdd e.g. today is 20011109, and I would like to get 20011108. Thank you!:confused: (2 Replies)
I have a file with some date columns in MM/DD/YYYY format:
SMPBR|DUP-DO NOT USE|NEW YORK||16105|BA5270715|6/6/2007 |MWERNER|109||||JOHN||SMITH|MD|72211118||||||74559|21 WILMINGTON RD||D|11/6/2003|SL# MD CONTACT-LIZ RICHARDS|||0|Y|N||1411458|
And I want to convert the date format to:
... (5 Replies)
In my shell script i have a variable which stores date in the format of YYYYMMDD. Is there any way to format this value to MM/DD/YYYY.
Thanks. (8 Replies)
Hi All,
I have a string like below.
"Mar 31 2009" .
I want to convert this to unix time .
Also please let me know how to find the unix time for the above string minus one day. For Eg. if i have string "Mar 31 2009" i want to find the unix time stamp of "Mar 30 2009".
Thanks in advance,... (11 Replies)
Hi All,
I am learning PERL for one of the projects, and in one of these scripts, I read a flat text file and print in the terminal.
The problem is, the text file has a date field. The format is yyyymmdd. I need to display this as dd-mon-yyyy.
Any ideas to do this? Thanks a lot for the... (9 Replies)
Hi,
I am getting the below string as a input for date.
12/03/2013 11:02 AM
I want to change this date as 03-DEC-2013 11:02 AM.
Could you please help on this.
Thanks
Chelladurai (4 Replies)
Hi All
I need help in converting a string of YYYYMMDD format to date in Sun OS and then find out if the day is a Wednesday or not. The "date -d" option is not working and your help is much appreciated.
The date command usage from the operating system we use here is as follows:
usage: ... (1 Reply)
Discussion started by: SK123
1 Replies
LEARN ABOUT CENTOS
cal
CAL(1) User Commands CAL(1)NAME
cal - display a calendar
SYNOPSIS
cal [options] [[[day] month] year]
DESCRIPTION
cal displays a simple calendar. If no arguments are specified, the current month is displayed.
OPTIONS -1, --one
Display single month output. (This is the default.)
-3, --three
Display prev/current/next month output.
-s, --sunday
Display Sunday as the first day of the week.
-m, --monday
Display Monday as the first day of the week.
-j, --julian
Display Julian dates (days one-based, numbered from January 1).
-y, --year
Display a calendar for the current year.
-V, --version
Display version information and exit.
-h, --help
Display help screen and exit.
PARAMETERS
A single parameter specifies the year (1 - 9999) to be displayed; note the year must be fully specified: cal 89 will not display a calendar
for 1989.
Two parameters denote the month (1 - 12) and year.
Three parameters denote the day (1-31), month and year, and the day will be highlighted if the calendar is displayed on a terminal. If no
parameters are specified, the current month's calendar is displayed.
A year starts on Jan 1. The first day of the week is determined by the locale.
The Gregorian Reformation is assumed to have occurred in 1752 on the 3rd of September. By this time, most countries had recognized the ref-
ormation (although a few did not recognize it until the early 1900's). Ten days following that date were eliminated by the reformation, so
the calendar for that month is a bit unusual.
HISTORY
A cal command appeared in Version 6 AT&T UNIX.
AVAILABILITY
The cal command is part of the util-linux package and is available from ftp://ftp.kernel.org/pub/linux/utils/util-linux/.
util-linux June 2011 CAL(1)