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Full Discussion: Bash for loop array
Top Forums Shell Programming and Scripting Bash for loop array Post 303015076 by mwheeler12 on Tuesday 27th of March 2018 10:50:27 AM
Old 03-27-2018
It works!
Thanks a lot. I changed it up a little to reformat the date. This is the complete solution:

Code:
for datestamp in $(find "$DPPATH" -name "${DBNAME}*.dmp.gz" $MTIMECMD -type f | tee "$tmpfile" | grep -Eo '[[:digit:]]{8}' | sort -u)
do
        grep "$datestamp" "$tmpfile" | while IFS="" read -r path
        do /usr/local/bin/aws s3 mv "$path" "s3://$S3BUCKET/export_area/$DBNAME/${datestamp:0:4}-${datestamp:4:2}-${datestamp:6:2}/"
        done
done

Thanks again.
 

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LEARN ABOUT LINUX

zegrep

ZGREP(1)                                                      General Commands Manual                                                     ZGREP(1)

NAME

       zgrep - search possibly compressed files for a regular expression

SYNOPSIS

       zgrep [ grep_options ] [ -e ] pattern filename...

DESCRIPTION

       Zgrep  invokes  grep  on  compressed  or  gzipped  files.   These  grep  options  will  cause  zgrep  to  terminate  with  an  error  code:
       (-[drRzZ]|--di*|--exc*|--inc*|--rec*|--nu*).  All other options specified are passed directly to grep.  If no file is specified,  then  the
       standard input is decompressed if necessary and fed to grep.  Otherwise the given files are uncompressed if necessary and fed to grep.

       If the GREP environment variable is set, zgrep uses it as the grep program to be invoked.

EXIT CODE

       2 - An option that is not supported was specified.

AUTHOR

       Charles Levert (charles@comm.polymtl.ca)

SEE ALSO

       grep(1), gzexe(1), gzip(1), zdiff(1), zforce(1), zmore(1), znew(1)

                                                                                                                                          ZGREP(1)
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