awk matching script not working as expected Post: 303014849

10 More Discussions You Might Find Interesting

1. Shell Programming and Scripting

which not working as expected

Hello. Consider the following magic words: # ls `which adduser` ls: /usr/sbin/adduser: No such file or directory # Hmmm... Then: # ls /usr/sbin/adduser /usr/sbin/adduser # Now what? Unforunately this little sniippet is used in my debian woody server's mysql pre install script....

2. Shell Programming and Scripting

awk not working as expected with BIG files ...

I am facing some strange problem. I know, there is only one record in a file 'test.txt' which starts with 'X' I ensure that with following command, awk /^X/ test.txt | wc -l This gives me output = '1'. Now I take out this record out of the file, as follows : awk /^X/ test.txt >...

3. Shell Programming and Scripting

Var substitution in awk - not working as expected

countA=`awk '/X/''{print substr($0,38,1)}' fName | wc -l` countB=`wc -l fName | awk '{print int($1)}'` echo > temp ratio=`awk -va=$countA -vc=$countB '{printf "%.4f", a/c}' temp` After running script for above I am getting an error as : awk: 0602-533 Cannot find or open file -vc=25. The...

4. Shell Programming and Scripting

bash variable (set via awk+sed) not working as expected

Hi! Been working on a script and I've been having a problem. I've finally narrowed it down to this variable I'm setting: servername=$(awk -v FS=\/ '{ print $7 } blah.txt | sed 's\/./-/g' | awk -v FS=\- '{print $1}')" This will essentially pare down a line like this: ...

5. Shell Programming and Scripting

Script not working as expected

Hi, I have prepared a script and trying to execute it but not getting expected output. Could you please help and advise what is going wrong. "If else" part in below script is not working basically. I am running it on HP-UX. for i in slpd puma sfmdb do echo "******\t$i\t*******" echo...

6. Shell Programming and Scripting

awk not working as expected in script

Dear all, I had script which used to work, but recently it is not working as expected. I have command line in my shell script to choose the following format from the output_elog and perform some task afterwards on As you see, I want all numbers in foramt following RED mark except for...

7. Shell Programming and Scripting

awk command not working as expected

Following one line of awk code removes first 3 characters from each line but when I run the same code on another linux platform it doesn't work and only prints blank lines for each record. Can anyone please explain why this doesn't work?

8. Shell Programming and Scripting

awk gsub not working as expected

Hi Experts, Need your kind help with gsub awk. Below is my pattern:"exec=1_host_cnt=100_dup=4_NameTag=targetSrv_500.csv","'20171122112948"," 100"," 1"," 1"," 4","400","","", " aac sample exec ""hostname=XXXXX commandline='timeout 10 openssl speed -multi 2 ; exit 0'"" ","-1","-1","1","...

9. UNIX for Beginners Questions & Answers

Passing Arguments to shell script from file is not working as expected.

Hi All, I have below simple shell script in cloudera quick start vm cenos 6 which copy file from source to destination. # file_copy.sh source_dir = ${source_dir} target = ${target_dir} cp source_dir target and my parameter file is like below #parameter_file.txt source_dir =...

10. UNIX for Beginners Questions & Answers

Why this script is not working as 'expected' when doing ssh with while read ... really confused?

Hi, I have a script below that is running ssh <host> <command> on some servers. Below is more or less the script. I have to modify it somehow to get rid of the 'confidential' hostnames check_log.bash #!/bin/bash # myPID=$$ parse_log () { sub="parse_log" host=${1} ...

LEARN ABOUT LINUX

lsb_release

lsb_release(1)						      General Commands Manual						    lsb_release(1)

NAME

       lsb_release - print distribution-specific information

SYNOPSIS

       lsb_release [options]

DESCRIPTION

       The lsb_release command provides certain LSB (Linux Standard Base) and distribution-specific information.

       If no options are given, the -v option is assumed.

OPTIONS

       The  program  follows  the  usual  GNU  command	line  syntax, with long options starting with two dashes (`--').  A summary of options are
       included below.

       -v, --version
	      Show the version of the LSB against which your current installation is compliant.  The version is expressed  as  a  colon  separated
	      list of LSB module descriptions.

       -i, --id
	      Display the distributor's ID.

       -d, --description
	      Display a description of the currently installed distribution.

       -r, --release
	      Display the release number of the currently installed distribution.

       -c, --codename
	      Display the code name of the currently installed distribution.

       -a, --all
	      Display all of the above information.

       -s, --short
	      Use the short output format for any information displayed.  This format omits the leading header(s).

       -h, --help
	      Show summary of options.

NOTES

       This  is a reimplementation of the lsb_release command provided by the Free Standards Group.  Any bugs are solely the responsibility of the
       author below.

       Detection of systems using a mix of packages from various distributions or releases is something of a  black  art;  the	current  heuristic
       tends  to assume that the installation is of the earliest distribution which is still being used by .B apt but that heuristic is subject to
       error.

SEE ALSO

       lsb(8)

AUTHOR

       Chris Lawrence <lawrencc@debian.org>.

																    lsb_release(1)