Hi,
I have writtena script that will recursivly go into subdirecotries and report out what files there are in there that have not been accessed over various date ranges.
I do this using a number of find commands:
find . -path './.snapshot' -prune -o -type f -atime -8
find... (4 Replies)
Hi,
Please anyone help to achive this using perl or unix scripting .
This is date in my table 20090224,based on the date need to check the files,If file exist for that date then increment by 1 for that date and check till max date 'i.e.20090301 and push those files .
files1_20090224... (2 Replies)
Hi All,
The developers want me to search and capture the weblogic log, you know this big logs of htmls.
They want to me to have ranges on the date and time. Like
from "2010-01-20 14:04:46,186" to "2010-01-20 15:00:12,490"
I can only do this,
cat /usr/local/bea/logs_prod1/debug.log |... (1 Reply)
Hi All,
The developers want me to search and capture the weblogic log, you know this big logs of htmls.
They want to me to have ranges on the date and time. Like
from "2010-01-20 14:04:46,186" to "2010-01-20 15:00:12,490"
I can only do this,
cat /usr/local/bea/logs_prod1/debug.log... (1 Reply)
Hello,
I would like for the user to input the date for a particular log file, then have the input sent to a variable, which is then used via grep to extra the logs for the specific date the user request.
I did some searching, but I still don't understand why I'm not seeing any result.
... (4 Replies)
Hello,
I have a text file which contains a list of strings which I want to grep from another file where these strings occur and print out only these lines.
I had earlier used the grep command
where File1 was the file containing the strings to be grepped (Source File) and File2 the Target File... (4 Replies)
Hello,
I have a data in file 1
2000000024776
2000000026979
2000000033355
2000000036309
2000000041291
2000000042679
2000000067221
and in file 2 its like this
2000000024776 16
2000000026979 16
2000000033355 16 (2 Replies)
Hi Guys,
I am having below tables used in oracle
bal
ID BALANCE BAL_DATE
1 -11.71 01-JAN-05 00.00.00
1 -405.71 02-JAN-05 00.00.00
1 -760.71 03-JAN-05 00.00.00
ref_table
PRODUCT EFF_FROM_DATE EFF_TO_DATE TYPE MIN_AMT MAX_AMT CHARGE
12 01-JAN-05 00.00.00 01-JAN-06... (6 Replies)
Hello,
I am a noob and need some help.
I am trying to find files created between a date range.
For Example:
These are files in directory.
-rw-r--r-- 1 user staff 6 May 8 09:43 file1.txt
-rw-r--r-- 1 user staff 6 May 8 09:43 file2.txt
-rw-r--r-- 1 user... (8 Replies)
Discussion started by: r@v!7*7@
8 Replies
LEARN ABOUT LINUX
shtool-path
SHTOOL-PATH.TMP(1) GNU Portable Shell Tool SHTOOL-PATH.TMP(1)NAME
shtool-path - GNU shtool command dealing with shell path variables
SYNOPSIS
shtool path [-s|--suppress] [-r|--reverse] [-d|--dirname] [-b|--basename] [-m|--magic] [-p|--path path] str [str ...]
DESCRIPTION
This command deals with shell $PATH variables. It can find a program through one or more filenames given by one or more str arguments. It
prints the absolute filesystem path to the program displayed on "stdout" plus an exit code of 0 if it was really found.
OPTIONS
The following command line options are available.
-s, --suppress
Supress output. Useful to only test whether a program exists with the help of the return code.
-r, --reverse
Transform a forward path to a subdirectory into a reverse path.
-d, --dirname
Output the directory name of str.
-b, --basename
Output the base name of str.
-m, --magic
Enable advanced magic search for ""perl"" and ""cpp"".
-p, --path path
Search in path. Default is to search in $PATH.
EXAMPLE
# shell script
awk=`shtool path -p "${PATH}:." gawk nawk awk`
perl=`shtool path -m perl`
cpp=`shtool path -m cpp`
revpath=`shtool path -r path/to/subdir`
HISTORY
The GNU shtool path command was originally written by Ralf S. Engelschall <rse@engelschall.com> in 1998 for Apache. It was later taken
over into GNU shtool.
SEE ALSO shtool(1), which(1).
18-Jul-2008 shtool 2.0.8 SHTOOL-PATH.TMP(1)