Hello Shell Guru's

I have a requirement to split the source xml file into three different text file.
And i need your valuable suggestion to finish this.

Here is my source xml snippet, here i am using only one entry of <jms-system-resource>. There may be multiple entries in the source file.

Code:

  <jms-system-resource>
    <name>UMSJMSSystemResource</name>
    <target>soa_server1,bam_server1</target>
    <sub-deployment>
      <name>UMSJMSServer522129776</name>
      <target>UMSJMSServer_auto_1</target>
    </sub-deployment>
    <sub-deployment>
      <name>UMSJMSServer1709690790</name>
      <target>UMSJMSServer_auto_2</target>
    </sub-deployment>
    <descriptor-file-name>jms/UMSJMSSystemResource-jms.xml</descriptor-file-name>
  </jms-system-resource>

we would like to have three separate files like below for the above file
1) DSFilenames.txt
2) JMSModule.txt
3) Subdeployment.txt

1) DSFilenames.txt should contains only the value of <descriptor-file-name>.
In the above example, the expected output should be like below

Code:

  dsfilename=jms/UMSJMSSystemResource-jms.xml

2) JMSModule.txt should contains values of <name>, <target> under <jms-system-resource>
In the above example, the expected output should be like below

Code:

  name=UMSJMSSystemResource
  target=soa_server1,bam_server1

3)Subdeployment.txt should contains values of <name>, <target> under each <sub-deployment> tag
In the above example, the expected output should be like below

Code:

   name= UMSJMSServer522129776
   target=UMSJMSServer_auto_1
   name=UMSJMSServer1709690790
   target=UMSJMSServer_auto_2

Any help on this will be deeply appreciated.