hi all UNIX Gurus,
this is my first post...so i posting this with great expectations:o...hoping to get the similar replies...
my question is....
need to get timestamp with millisecond in UNIX. Date command gives Year,month day, hour,minute and second but it does not give millisecond.
Any... (5 Replies)
It is required to calculate time difference in seconds between epoch time (19700101 00:00:00) and any given date time (e.g. 20010214 14:30:30).
Is there any command in unix to get it? Thanks in adv. (1 Reply)
Need a little help developing a ksh script. Have read through Perderabo's datecalc routine and it does not seem to fit the function I am looking for. Basically what I am trying to do is find any file (in a specific directory) that was created within the last five minutes. I am not a programming... (3 Replies)
I am trying to get the ellapsed time in seconds in the body of the awk script. I use unix date to get the time. It works in BEGIN {} but not in the body {} of awk. Any ideas?
$ cat a
BEGIN {
"date +%s" | getline x
print x
}
{
"date +%s" | getline y
print y
}
$ echo "one line" |... (3 Replies)
I'd like to convert a date string in the form of sun aug 19 09:03:10 EDT 2012, to unixtime timestamp using awk.
I tried
This is how each line of the file looks like, different date and time in this format
Sun Aug 19 08:33:45 EDT 2012, user1(108.6.217.236) all: test on the 17th
... (2 Replies)
Hi to everybody
again i Need your help, i wasting hours but can't find a solutuin for my Problem. I am not an expert with AIX script programming.
I have a csh script and i need the time in seconds but since i have an old AIX the Option -%s doesnot exist with the date command. I seach in Google... (13 Replies)
Hello,
How can we convert date like format 20181004171050 in seconds ?
I can able to convert till date but failing for HHMMSS.
date -d "20181004" "+%s" output as 1538596800 .
But when i add hhmmss it is failing date -d "20181004172000" "+%s" result Invalid date
Kindly guide.
Regards (16 Replies)
Hello everyone,
I calculate in my bash script the different between two timestamps in seconds. The next step would be to get the difference in minutes, and there is my Problem:AnzahlUeberstunden=$(( $(date -d "$JAHR-$MONAT-$TAG $ArbeitEnde" +%s) - $(date -d "$JAHR-$MONAT-$TAG... (6 Replies)
Discussion started by: Chaos_Lord
6 Replies
LEARN ABOUT PHP
get_midi_length
get_midi_length(3alleg4) Allegro manual get_midi_length(3alleg4)NAME
get_midi_length - Determines the total playing time of a midi, in seconds. Allegro game programming library.
SYNOPSIS
#include <allegro.h>
int get_midi_length(MIDI *midi);
DESCRIPTION
This function will simulate playing the given MIDI, from start to end, to determine how long it takes to play. After calling this function,
midi_pos will contain the negative number of beats, and midi_time the length of the midi, in seconds.
Note that any currently playing midi is stopped when you call this function. Usually you would call it before play_midi, to get the length
of the midi to be played, like in this example:
length = get_midi_length(my_midi);
play_midi(my_midi);
do {
pos = midi_time;
textprintf_ex(screen, font, 0, 0, c, -1, "%d:%02d / %d:%02d
",
pos / 60, pos % 60, length / 60, length % 60);
rest(100);
} while(pos <= length);
RETURN VALUE
Returns the value of midi_time, the length of the midi.
SEE ALSO load_midi(3alleg4), midi_time(3alleg4), midi_pos(3alleg4), exmidi(3alleg4)Allegro version 4.4.2 get_midi_length(3alleg4)