hi all UNIX Gurus,
this is my first post...so i posting this with great expectations:o...hoping to get the similar replies...
my question is....
need to get timestamp with millisecond in UNIX. Date command gives Year,month day, hour,minute and second but it does not give millisecond.
Any... (5 Replies)
It is required to calculate time difference in seconds between epoch time (19700101 00:00:00) and any given date time (e.g. 20010214 14:30:30).
Is there any command in unix to get it? Thanks in adv. (1 Reply)
Need a little help developing a ksh script. Have read through Perderabo's datecalc routine and it does not seem to fit the function I am looking for. Basically what I am trying to do is find any file (in a specific directory) that was created within the last five minutes. I am not a programming... (3 Replies)
I am trying to get the ellapsed time in seconds in the body of the awk script. I use unix date to get the time. It works in BEGIN {} but not in the body {} of awk. Any ideas?
$ cat a
BEGIN {
"date +%s" | getline x
print x
}
{
"date +%s" | getline y
print y
}
$ echo "one line" |... (3 Replies)
I'd like to convert a date string in the form of sun aug 19 09:03:10 EDT 2012, to unixtime timestamp using awk.
I tried
This is how each line of the file looks like, different date and time in this format
Sun Aug 19 08:33:45 EDT 2012, user1(108.6.217.236) all: test on the 17th
... (2 Replies)
Hi to everybody
again i Need your help, i wasting hours but can't find a solutuin for my Problem. I am not an expert with AIX script programming.
I have a csh script and i need the time in seconds but since i have an old AIX the Option -%s doesnot exist with the date command. I seach in Google... (13 Replies)
Hello,
How can we convert date like format 20181004171050 in seconds ?
I can able to convert till date but failing for HHMMSS.
date -d "20181004" "+%s" output as 1538596800 .
But when i add hhmmss it is failing date -d "20181004172000" "+%s" result Invalid date
Kindly guide.
Regards (16 Replies)
Hello everyone,
I calculate in my bash script the different between two timestamps in seconds. The next step would be to get the difference in minutes, and there is my Problem:AnzahlUeberstunden=$(( $(date -d "$JAHR-$MONAT-$TAG $ArbeitEnde" +%s) - $(date -d "$JAHR-$MONAT-$TAG... (6 Replies)
Discussion started by: Chaos_Lord
6 Replies
LEARN ABOUT SUSE
time
TIME(2) Linux Programmer's Manual TIME(2)NAME
time - get time in seconds
SYNOPSIS
#include <time.h>
time_t time(time_t *t);
DESCRIPTION
time() returns the time as the number of seconds since the Epoch, 1970-01-01 00:00:00 +0000 (UTC).
If t is non-NULL, the return value is also stored in the memory pointed to by t.
RETURN VALUE
On success, the value of time in seconds since the Epoch is returned. On error, ((time_t) -1) is returned, and errno is set appropriately.
ERRORS
EFAULT t points outside your accessible address space.
CONFORMING TO
SVr4, 4.3BSD, C89, C99, POSIX.1-2001. POSIX does not specify any error conditions.
NOTES
POSIX.1 defines seconds since the Epoch as a value to be interpreted as the number of seconds between a specified time and the Epoch,
according to a formula for conversion from UTC equivalent to conversion on the naive basis that leap seconds are ignored and all years
divisible by 4 are leap years. This value is not the same as the actual number of seconds between the time and the Epoch, because of leap
seconds and because clocks are not required to be synchronized to a standard reference. The intention is that the interpretation of sec-
onds since the Epoch values be consistent; see POSIX.1 Annex B 2.2.2 for further rationale.
SEE ALSO date(1), gettimeofday(2), ctime(3), ftime(3), time(7)COLOPHON
This page is part of release 3.25 of the Linux man-pages project. A description of the project, and information about reporting bugs, can
be found at http://www.kernel.org/doc/man-pages/.
Linux 2010-02-25 TIME(2)