hi all UNIX Gurus,
this is my first post...so i posting this with great expectations:o...hoping to get the similar replies...
my question is....
need to get timestamp with millisecond in UNIX. Date command gives Year,month day, hour,minute and second but it does not give millisecond.
Any... (5 Replies)
It is required to calculate time difference in seconds between epoch time (19700101 00:00:00) and any given date time (e.g. 20010214 14:30:30).
Is there any command in unix to get it? Thanks in adv. (1 Reply)
Need a little help developing a ksh script. Have read through Perderabo's datecalc routine and it does not seem to fit the function I am looking for. Basically what I am trying to do is find any file (in a specific directory) that was created within the last five minutes. I am not a programming... (3 Replies)
I am trying to get the ellapsed time in seconds in the body of the awk script. I use unix date to get the time. It works in BEGIN {} but not in the body {} of awk. Any ideas?
$ cat a
BEGIN {
"date +%s" | getline x
print x
}
{
"date +%s" | getline y
print y
}
$ echo "one line" |... (3 Replies)
I'd like to convert a date string in the form of sun aug 19 09:03:10 EDT 2012, to unixtime timestamp using awk.
I tried
This is how each line of the file looks like, different date and time in this format
Sun Aug 19 08:33:45 EDT 2012, user1(108.6.217.236) all: test on the 17th
... (2 Replies)
Hi to everybody
again i Need your help, i wasting hours but can't find a solutuin for my Problem. I am not an expert with AIX script programming.
I have a csh script and i need the time in seconds but since i have an old AIX the Option -%s doesnot exist with the date command. I seach in Google... (13 Replies)
Hello,
How can we convert date like format 20181004171050 in seconds ?
I can able to convert till date but failing for HHMMSS.
date -d "20181004" "+%s" output as 1538596800 .
But when i add hhmmss it is failing date -d "20181004172000" "+%s" result Invalid date
Kindly guide.
Regards (16 Replies)
Hello everyone,
I calculate in my bash script the different between two timestamps in seconds. The next step would be to get the difference in minutes, and there is my Problem:AnzahlUeberstunden=$(( $(date -d "$JAHR-$MONAT-$TAG $ArbeitEnde" +%s) - $(date -d "$JAHR-$MONAT-$TAG... (6 Replies)
Discussion started by: Chaos_Lord
6 Replies
LEARN ABOUT MOJAVE
echo
ECHO(1) BSD General Commands Manual ECHO(1)NAME
echo -- write arguments to the standard output
SYNOPSIS
echo [-n] [string ...]
DESCRIPTION
The echo utility writes any specified operands, separated by single blank (' ') characters and followed by a newline ('
') character, to the
standard output.
The following option is available:
-n Do not print the trailing newline character. This may also be achieved by appending 'c' to the end of the string, as is done by iBCS2
compatible systems. Note that this option as well as the effect of 'c' are implementation-defined in IEEE Std 1003.1-2001
(``POSIX.1'') as amended by Cor. 1-2002. Applications aiming for maximum portability are strongly encouraged to use printf(1) to sup-
press the newline character.
Some shells may provide a builtin echo command which is similar or identical to this utility. Most notably, the builtin echo in sh(1) does
not accept the -n option. Consult the builtin(1) manual page.
EXIT STATUS
The echo utility exits 0 on success, and >0 if an error occurs.
SEE ALSO builtin(1), csh(1), printf(1), sh(1)STANDARDS
The echo utility conforms to IEEE Std 1003.1-2001 (``POSIX.1'') as amended by Cor. 1-2002.
BSD April 12, 2003 BSD