Sponsored Content
Top Forums Shell Programming and Scripting Sum the fields with 6 decimal places - getting only 2 decimal places as output Post 303013461 by vgersh99 on Wednesday 21st of February 2018 05:05:04 PM
Old 02-21-2018
use printf instead:
Code:
awk -F "|" '{a[$2$3$4$5$6$7]+=$8;}END{for(i in a)printf("%s%s%.6f\n",  i, OFS, a[i];}' OFS='|' file1

 

9 More Discussions You Might Find Interesting

1. Shell Programming and Scripting

trimm up the decimal places in output

I have a perl script that reports the avg time of a application call and the total number of calls. This works fine, however I would like to trim the number of decimal places reported from 12 to like 3 and I don't know how. Any suggestions? Here is what I use to get the avg time... for $eRef (... (2 Replies)
Discussion started by: theninja
2 Replies

2. Shell Programming and Scripting

Using the "Less Than" (-lt) switch on numbers with decimal places?

I'm using shell scripts to run some commands for the Configuration Management tool called Telelogic Synergy. I need to get the script to compare version numbers of files. The version numbers of the files are part of the actual filename, such as the following example: example_file-1... (7 Replies)
Discussion started by: Glyn_Mo
7 Replies

3. Shell Programming and Scripting

Four decimal places with awk

i have a script in which awk prints "($2-1700)/10000" and the answer is -0.07,but i want the answer in 4 decimal places. that is -0.0700. How can i sue awk to get my results in four decimal places (4 Replies)
Discussion started by: tomjones
4 Replies

4. Shell Programming and Scripting

Decimal places

i need to multiplay a number with 1.00.. so that the output should contain two decimal places at end.. for example... 236 * 1.00 = 236.00 245.8 * 1.00 = 245.80 but when i perform multiplication it shows output as. 236 245.8 can anyone help me to get the actual output of... (11 Replies)
Discussion started by: arunmanas
11 Replies

5. Shell Programming and Scripting

Arithmetic but keep 2 decimal places

I am trying to perform arithmetric, for example, to increment the value of variable $a (say 3) by 0.05 but when I tried the following expression let a=a+0.05 or a=$((a+0.05)) both returned 3.0499999999999998 I want to keep 2 decimal places so it returns 3.05 instead. (6 Replies)
Discussion started by: piynik
6 Replies

6. Shell Programming and Scripting

Bash Rounding to 2 decimal places

I have a number in a bash variable n, and want to round it to 2 decimal places. How can I do that? n=0.0867268 Need to have num=0.09 (1 Reply)
Discussion started by: kristinu
1 Replies

7. Shell Programming and Scripting

How to round up value upto 2 decimal places using sed?

Please help me in rounding up value upto 2 decimal palces using sed command #!/usr/bin/bash a=15.42 b=13.33 c=`echo $a*$b |bc -l` echo $c above code is is giving output "205.5486" but i want the output as "205.55" Thank you... (15 Replies)
Discussion started by: ranabhavish
15 Replies

8. Shell Programming and Scripting

Printing with decimal places from last 4 digits

I have input file like below, 201424|9999|OSS|622010|RGT|00378228764 201424|8888|OM|587079|RGT|00284329675 201424|7777|OM|587076|RGT|00128671024 201424|6666|OM|581528|RGT|00113552084 Output should be like below, should add decimal (.) from last 4 digits. ... (2 Replies)
Discussion started by: vinothsekark
2 Replies

9. Shell Programming and Scripting

Calculate the constant e to 14+ decimal places using integer maths.

Hi guys... I am loving this integer maths thing. 64 bit systems are certainly easier than 32 bit, but hey, I don't intend to leave out my fav' platform. Using one of the 'Brothers' methods, URL inside the code. #!/bin/sh # # #!/usr/local/bin/dash # e_constant.sh # Brother's formula . #... (2 Replies)
Discussion started by: wisecracker
2 Replies
END(3)							     Linux Programmer's Manual							    END(3)

NAME
etext, edata, end - end of program segments SYNOPSIS
extern etext; extern edata; extern end; DESCRIPTION
The addresses of these symbols indicate the end of various program segments: etext This is the first address past the end of the text segment (the program code). edata This is the first address past the end of the initialized data segment. end This is the first address past the end of the uninitialized data segment (also known as the BSS segment). CONFORMING TO
Although these symbols have long been provided on most Unix systems, they are not standardized; use with caution. NOTES
The program must explicitly declare these symbols; they are not defined in any header file. On some systems the names of these symbols are preceded by underscores, thus: _etext, _edata, and _end. These symbols are also defined for programs compiled on Linux. At the start of program execution, the program break will be somewhere near &end (perhaps at the start of the following page). However, the break will change as memory is allocated via brk(2) or malloc(3). Use sbrk(2) with an argument of zero to find the current value of the program break. EXAMPLE
When run, the program below produces output such as the following: $ ./a.out First address past: program text (etext) 0x8048568 initialized data (edata) 0x804a01c uninitialized data (end) 0x804a024 Program source #include <stdio.h> #include <stdlib.h> extern char etext, edata, end; /* The symbols must have some type, or "gcc -Wall" complains */ int main(int argc, char *argv[]) { printf("First address past: "); printf(" program text (etext) %10p ", &etext); printf(" initialized data (edata) %10p ", &edata); printf(" uninitialized data (end) %10p ", &end); exit(EXIT_SUCCESS); } SEE ALSO
objdump(1), readelf(1), sbrk(2), elf(5) COLOPHON
This page is part of release 3.25 of the Linux man-pages project. A description of the project, and information about reporting bugs, can be found at http://www.kernel.org/doc/man-pages/. GNU
2008-07-17 END(3)
All times are GMT -4. The time now is 09:20 PM.
Unix & Linux Forums Content Copyright 1993-2022. All Rights Reserved.
Privacy Policy