For example I cannot put all the files in a string when running a script as the amount of files is enormous. Also I cannot use a file display program such as Nautilus, the screen takes too long to load all the files.
I then need to run a program with each file as input to a program called mseed2sac and
may create multiple files for each file passed.
Now I want the script to give me a percentage so that user will know the progress. Ideally
I do not want that every calculation is printed on a new line. The following does not seen to
work well.
Can I find wether a particular file exist and size greater than zero in one line command.
similar to this
if &&
something in one if test .... e.g. if
1.) is it possible ? ... if yes how
2.) what would be the return type in case there is success or failure. I mean if both are... (4 Replies)
Hello,
I have the following problem. I know there is a file somewhere on a UNIX machine that contains a string, but I don't know where.
With the "grep" command, I can look into a file but only if I'm located in the correct directory.
With the "find" command, I can search across directories... (2 Replies)
Yes , I have to find a file in unix without using any find or where commands.Any pointers for the same would be very helpful as i am beginner in shell scritping and need a solution for the same.
Thanks in advance.
Regards
Jatin Jain (10 Replies)
Hi,
I know how to use the test command ( ...) to find a single given name file.
However, I have a case in which I have a directory with one file and one sub-directory. I know that the file starts with "fub".
The command doesn't work if i call the file "fub*" as it doesn't understand I meant a... (2 Replies)
I have the following data stored in a file.
1 /home/file13 /home/file2
2 /home/file41 /home/file654
3 /home/file61 /home/file45
4 /home/file81 /home/file43
...
I want to print the first column provided the files represented by the second and third column exist.
How to do that? (3 Replies)
hi frnds,
please help ... what will happen with below command if destination path does not exist on the system....
find /var/adm/cft* -mtime +1 -exec mv {} /global/ \ in unix
its remove all my files from the system from soruce file ... how is it possbile (1 Reply)
Hi All,
Can anyone give me the command to copy files from 03-Mar-2013 to 07-Mar-2013 in folder.
there are nearly 40+ thousand files in directory , so I just need files from Mar 3rd to Mar 7th and copy them to a location .
Need quick help pls (2 Replies)
Hello,
i want to script on sh to check from a path if the directory exist and isn't empty.
I explain:
path is : /aaa/bbb/ccc/ccc_name/ddd/
Where the cccc_name is in a list, so i think it's $1
My command
find -name /aaa/bbb/ccc/$1/ddd/ didn't work because my $1 is the same and not... (5 Replies)
I need to find a word '% Retail by State' in the folder /usr/sas/reports/RetailSalesTaxallocation.
When I tried like below,
-bash-4.1$ cd /usr/sas/reports/RetailSalesTaxallocation
-bash-4.1$ find ./ -name % Retail by State
find: paths must precede expression: Retail
Usage: find ... (10 Replies)
Discussion started by: Ram Kumar_BE
10 Replies
LEARN ABOUT DEBIAN
file::find::wanted
Wanted(3pm) User Contributed Perl Documentation Wanted(3pm)NAME
File::Find::Wanted - More obvious wrapper around File::Find
VERSION
Version 1.00
SYNOPSIS
File::Find is a great module, except that it doesn't actually find anything. Its "find()" function walks a directory tree and calls a
callback function. Unfortunately, the callback function is deceptively called "wanted", which implies that it should return a boolean
saying whether you want the file. That's not how it works.
Most of the time you call "find()", you just want to build a list of files. There are other modules that do this for you, most notably
Richard Clamp's great File::Find::Rule, but in many cases, it's overkill, and you need to learn a new syntax.
With the "find_wanted" function, you supply a callback sub and a list of starting directories, but the sub actually should return a boolean
saying whether you want the file in your list or not.
To get a list of all files ending in .jpg:
my @files = find_wanted( sub { -f && /.jpg$/ }, $dir );
For a list of all directories that are not CVS or .svn:
my @files = find_wanted( sub { -d && !/^(CVS|.svn)$/ }, $dir ) );
It's easy, direct, and simple.
WHY DO THIS ?
The cynical may say "that's just the same as doing this":
my @files;
find( sub { push @files, $File::Find::name if -f && /.jpg$/ }, $dir );
Sure it is, but File::Find::Wanted makes it more obvious, and saves a line of code. That's worth it to me. I'd like it if find_wanted()
made its way into the File::Find distro, but for now, this will do.
FUNCTIONS
find_wanted( &wanted, @directories )
Descends through @directories, calling the wanted function as it finds each file. The function returns a list of all the files and
directories for which the wanted function returned a true value.
This is just a wrapper around "File::Find::find()". See File::Find for details on how to modify its behavior.
COPYRIGHT & LICENSE
Copyright 2005-2012 Andy Lester.
This program is free software; you can redistribute it and/or modify it under the terms of the Artistic License v2.0.
perl v5.14.2 2012-06-08 Wanted(3pm)