Sum the fields with 6 decimal places - getting only 2 decimal places as output
I used the below script to Sum up a field in a file based on some unique values. But the problem is when it is summing up the units, it is truncating to 2 decimals and not 6 decimals as in the input file (Input file has the units with up to 6 Decimals – Sample data below, when the units in the 2 rows below highlighted in red are added, I only get 2 decimal places 18.34).
I have a perl script that reports the avg time of a application call and the total number of calls. This works fine, however I would like to trim the number of decimal places reported from 12 to like 3 and I don't know how.
Any suggestions? Here is what I use to get the avg time...
for $eRef (... (2 Replies)
I'm using shell scripts to run some commands for the Configuration Management tool called Telelogic Synergy.
I need to get the script to compare version numbers of files. The version numbers of the files are part of the actual filename, such as the following example:
example_file-1... (7 Replies)
i have a script in which awk prints "($2-1700)/10000"
and the answer is -0.07,but i want the answer in 4 decimal places.
that is -0.0700.
How can i sue awk to get my results in four decimal places (4 Replies)
i need to multiplay a number with 1.00.. so that the output should contain two decimal places at end..
for example...
236 * 1.00 = 236.00
245.8 * 1.00 = 245.80
but when i perform multiplication it shows output as.
236
245.8
can anyone help me to get the actual output of... (11 Replies)
I am trying to perform arithmetric, for example, to increment the value of variable $a (say 3) by 0.05 but when I tried the following expression
let a=a+0.05
or a=$((a+0.05))
both returned
3.0499999999999998
I want to keep 2 decimal places so it returns 3.05 instead. (6 Replies)
Please help me in rounding up value upto 2 decimal palces using sed command
#!/usr/bin/bash
a=15.42
b=13.33
c=`echo $a*$b |bc -l`
echo $c
above code is is giving output "205.5486" but i want the output as "205.55"
Thank you... (15 Replies)
I have input file like below,
201424|9999|OSS|622010|RGT|00378228764
201424|8888|OM|587079|RGT|00284329675
201424|7777|OM|587076|RGT|00128671024
201424|6666|OM|581528|RGT|00113552084
Output should be like below, should add decimal (.) from last 4 digits.
... (2 Replies)
Hi guys...
I am loving this integer maths thing.
64 bit systems are certainly easier than 32 bit, but hey, I don't intend to leave out my fav' platform.
Using one of the 'Brothers' methods, URL inside the code.
#!/bin/sh
#
# #!/usr/local/bin/dash
# e_constant.sh
# Brother's formula .
#... (2 Replies)
Discussion started by: wisecracker
2 Replies
LEARN ABOUT CENTOS
grub-render-label
GRUB-RENDER-LABEL(1) User Commands GRUB-RENDER-LABEL(1)NAME
grub-render-label - generate a .disk_label for Apple Macs.
SYNOPSIS
grub-render-label [OPTION...] [OPTIONS]
DESCRIPTION
Render Apple .disk_label.
-b, --bgcolor=COLOR
use COLOR for background
-c, --color=COLOR
use COLOR for text
-f, --font=FILE
use FILE as font (PF2).
-i, --input=FILE
read text from FILE.
-o, --output=FILE
set output filename. Default is STDOUT
-t, --text=STRING
set the label to render
-v, --verbose
print verbose messages.
-?, --help
give this help list
--usage
give a short usage message
-V, --version
print program version
Mandatory or optional arguments to long options are also mandatory or optional for any corresponding short options.
REPORTING BUGS
Report bugs to <bug-grub@gnu.org>.
SEE ALSO
The full documentation for grub-render-label is maintained as a Texinfo manual. If the info and grub-render-label programs are properly
installed at your site, the command
info grub-render-label
should give you access to the complete manual.
grub-render-label (GRUB) 2.02-2ubuntu8.3 July 2018 GRUB-RENDER-LABEL(1)
02-15-2018
