Sponsored Content
Top Forums Shell Programming and Scripting Get a given date and subtract it to 5 days ago Post 303013007 by MadeInGermany on Tuesday 13th of February 2018 03:11:26 PM
Old 02-13-2018
Code:
today_plus_5=$(date --date="today + 5 days" +%s)
expire=$(date --date="13-Feb-19" +%s)
if [ $today_plus_5 -ge $expire ]; then echo "will expire in 5 days"; fi

Or
Code:
today=$(date +%s)
expire_minus_5=$(date --date="13-Feb-19 - 5 days" +%s)
if [ $today -ge $expire_minus_5 ]; then echo "will expire in 5 days"; fi

 

10 More Discussions You Might Find Interesting

1. Shell Programming and Scripting

date for two days or 3 days ago

i need a script that can tell me the date 2 days ago or 3 days ago. please help (7 Replies)
Discussion started by: tomjones
7 Replies

2. Shell Programming and Scripting

Subtract days from a variable holding date

Hi, could someone help on this.. I have a date in variable procdate="05/30/2009" I would want to Subtract it with 3 or 4 (2 Replies)
Discussion started by: infernalhell
2 Replies

3. Shell Programming and Scripting

how to get what date was 28 days ago of the current system date IN UNIX

Hi, Anybody knows how to get what date was 28 days ago of the current system date through UNIX script. Ex : - If today is 28th Mar 2010 then I have to delete the files which arrived on 1st Mar 2010, (15 Replies)
Discussion started by: kandi.reddy
15 Replies

4. Shell Programming and Scripting

Date within a timeframe 2 days ago

How could I using the following example, change it to show 2 days ago within the same time frame 0600 AM to 0600 AM let foo=`date "+(1%H-106)*60+1%M-100"` bar=foo+1440 find . -mmin +$foo -mmin -$bar | tr -s '/','-' '^' | cut -f2,3 -d"^" | tr -s '^' ' ' | Please use code tags (7 Replies)
Discussion started by: freddie999
7 Replies

5. Shell Programming and Scripting

Calculating 7 days ago date for the given Argument

Hi I have shell script and I am facing the below issue to integrate the date calculation to the the script. If I give the $1 as the date(20110701) then I need to get the 7 days ago date for the same format.(20110624). At first I thought its a simple one to handle and I did a search in the... (10 Replies)
Discussion started by: filter
10 Replies

6. UNIX for Advanced & Expert Users

Subtract days to a date in AIX 5.3

good afternoon, can someone help me, I need to make a script where n subtract days to a date. I am using AIX 5.3. Greetings. (4 Replies)
Discussion started by: systemoper
4 Replies

7. Shell Programming and Scripting

Subtract 2 date columns in .csv file and get output as number of days

Hi, I have one .csv file. I have 2 date columns present in file, column 2 and column 3. I need to calculate how many days exist between 2 dates. I am trying to subtract date column 2 from date column 3. Eg: my file look likes s.no, Start_date,End_Date 1, 7/29/2012,10/27/2012 2,... (9 Replies)
Discussion started by: Dimple
9 Replies

8. Shell Programming and Scripting

Subtract months/days from date

Hi, Can you please let me know code for the below (in korn shell) a) Subtract month(s) from given date b) Subtract day(s) from give date c) Subtract month(s) from given timestamp d) Subtract day(s) from give timestamp (1 Reply)
Discussion started by: tostay2003
1 Replies

9. UNIX for Beginners Questions & Answers

How to find a file that's modified more than 2 days ago but less than 5 days ago?

How to find a file that's modified more than 2 days ago but was modified less than 5 days ago by use of any Linux utility ? (4 Replies)
Discussion started by: abdulbadii
4 Replies

10. HP-UX

awk command in hp UNIX subtract 30 days automatically from current date without date illegal option

current date command runs well awk -v t="$(date +%Y-%m-%d)" -F "'" '$1 < t' myname.dat subtract 30 days fails awk -v t="$(date --date="-30days" +%Y-%m-%d)" -F "'" '$1 < t' myname.dat awk command in hp unix subtract 30 days automatically from current date without date illegal option error... (20 Replies)
Discussion started by: kmarcus
20 Replies
CHAGE(1)						      General Commands Manual							  CHAGE(1)

NAME
chage - change user password expiry information SYNOPSIS
chage [-m mindays] [-M maxdays] [-d lastday] [-I inactive] [-E expiredate] [-W warndays] user chage -l user DESCRIPTION
chage changes the number of days between password changes and the date of the last password change. This information is used by the system to determine when a user must change her password. The chage command is restricted to the root user, except for the -l option, which may be used by an unprivileged user to determine when her password or account is due to expire. With the -m option, the value of mindays is the minimum number of days between password changes. A value of zero for this field indicates that the user may change her password at any time. With the -M option, the value of maxdays is the maximum number of days during which a password is valid. When maxdays plus lastday is less than the current day, the user will be required to change her password before being able to use her account. This occurance can be planned for in advance by use of the -W option, which provides the user with advance warning. With the -d option, the value of lastday is the number of days since January 1st, 1970 when the password was last changed. The date may also be expressed in the format YYYY-MM-DD (or the format more commonly used in your area). The -E option is used to set a date on which the user's account will no longer be accessible. The expiredate option is the number of days since January 1, 1970 on which the accounted is locked. The date may also be expressed in the format YYYY-MM-DD (or the format more com- monly used in your area). A user whose account is locked must contact the system administrator before being able to use the system again. The -I option is used to set the number of days of inactivity after a password has expired before the account is locked. The inactive option is the number of days of inactivity. A value of 0 disables this feature. A user whose account is locked must contact the system administrator before being able to use the system again. The -W option is used to set the number of days of warning before a password change is required. The warndays option is the number of days prior to the password expiring that a user will be warned her password is about to expire. If none of the options are selected, chage operates in an interactive fashion, prompting the user with the current values for all of the fields. Enter the new value to change the field, or leave the line blank to use the current value. The current value is displayed between a pair of [ ] marks. NOTE
The chage program requires shadow password file to be available. Its functionality is not available when passwords are stored in the passwd file. FILES
/etc/passwd - user account information /etc/shadow - shadow user account information SEE ALSO
passwd(5), shadow(5) AUTHOR
Julianne Frances Haugh <jockgrrl@ix.netcom.com> CHAGE(1)
All times are GMT -4. The time now is 01:02 AM.
Unix & Linux Forums Content Copyright 1993-2022. All Rights Reserved.
Privacy Policy