I have been researching to obtain SSL certification expiry for most of our webistes. For some cases, some hosts where not directly accessible so i finally got a solution working with curl using my proxy. This lists the expiry date which i'm finally looking for.
The next step is to try to find a way to get notified 5 days before that date (no emails).
First thoughts are to extract the date using awk/sed from the above result and convert it to epoch:
Then i was thinking to somehow subtract this date to 5 days ago and convert it to epoch time. With both values in hand i subtract and the difference will be the said threshold. if less then, it means less then 5 days prior to expiry.
However i don't see how we can get a GIVEN date and subtract.
Do you have some thoughts or maybe other ideas?
Hi,
Anybody knows how to get what date was 28 days ago of the current system date through UNIX script.
Ex : - If today is 28th Mar 2010 then I have to delete the files which arrived on 1st Mar 2010, (15 Replies)
How could I using the following example, change it to show 2 days ago within the same time frame 0600 AM to 0600 AM
let foo=`date "+(1%H-106)*60+1%M-100"` bar=foo+1440
find . -mmin +$foo -mmin -$bar | tr -s '/','-' '^' | cut -f2,3 -d"^" | tr -s '^' ' ' |
Please use code tags (7 Replies)
Hi
I have shell script and I am facing the below issue to integrate the date calculation to the the script.
If I give the $1 as the date(20110701) then I need to get the 7 days ago date for the same format.(20110624).
At first I thought its a simple one to handle and I did a search in the... (10 Replies)
Hi,
I have one .csv file. I have 2 date columns present in file, column 2 and column 3.
I need to calculate how many days exist between 2 dates.
I am trying to subtract date column 2 from date column 3.
Eg: my file look likes
s.no, Start_date,End_Date
1, 7/29/2012,10/27/2012
2,... (9 Replies)
Hi,
Can you please let me know code for the below (in korn shell)
a) Subtract month(s) from given date
b) Subtract day(s) from give date
c) Subtract month(s) from given timestamp
d) Subtract day(s) from give timestamp (1 Reply)
current date command runs well
awk -v t="$(date +%Y-%m-%d)" -F "'" '$1 < t' myname.dat
subtract 30 days fails
awk -v t="$(date --date="-30days" +%Y-%m-%d)" -F "'" '$1 < t' myname.dat
awk command in hp unix subtract 30 days automatically from current date without date illegal option error... (20 Replies)
Discussion started by: kmarcus
20 Replies
LEARN ABOUT CENTOS
chage
CHAGE(1) User Commands CHAGE(1)NAME
chage - change user password expiry information
SYNOPSIS
chage [options] LOGIN
DESCRIPTION
The chage command changes the number of days between password changes and the date of the last password change. This information is used by
the system to determine when a user must change his/her password.
OPTIONS
The options which apply to the chage command are:
-d, --lastday LAST_DAY
Set the number of days since January 1st, 1970 when the password was last changed. The date may also be expressed in the format
YYYY-MM-DD (or the format more commonly used in your area).
-E, --expiredate EXPIRE_DATE
Set the date or number of days since January 1, 1970 on which the user's account will no longer be accessible. The date may also be
expressed in the format YYYY-MM-DD (or the format more commonly used in your area). A user whose account is locked must contact the
system administrator before being able to use the system again.
Passing the number -1 as the EXPIRE_DATE will remove an account expiration date.
-h, --help
Display help message and exit.
-I, --inactive INACTIVE
Set the number of days of inactivity after a password has expired before the account is locked. The INACTIVE option is the number of
days of inactivity. A user whose account is locked must contact the system administrator before being able to use the system again.
Passing the number -1 as the INACTIVE will remove an account's inactivity.
-l, --list
Show account aging information.
-m, --mindays MIN_DAYS
Set the minimum number of days between password changes to MIN_DAYS. A value of zero for this field indicates that the user may change
his/her password at any time.
-M, --maxdays MAX_DAYS
Set the maximum number of days during which a password is valid. When MAX_DAYS plus LAST_DAY is less than the current day, the user
will be required to change his/her password before being able to use his/her account. This occurrence can be planned for in advance by
use of the -W option, which provides the user with advance warning.
Passing the number -1 as MAX_DAYS will remove checking a password's validity.
-R, --root CHROOT_DIR
Apply changes in the CHROOT_DIR directory and use the configuration files from the CHROOT_DIR directory.
-W, --warndays WARN_DAYS
Set the number of days of warning before a password change is required. The WARN_DAYS option is the number of days prior to the
password expiring that a user will be warned his/her password is about to expire.
If none of the options are selected, chage operates in an interactive fashion, prompting the user with the current values for all of the
fields. Enter the new value to change the field, or leave the line blank to use the current value. The current value is displayed between a
pair of [ ] marks.
NOTE
The chage program requires a shadow password file to be available.
The chage command is restricted to the root user, except for the -l option, which may be used by an unprivileged user to determine when
his/her password or account is due to expire.
CONFIGURATION
The following configuration variables in /etc/login.defs change the behavior of this tool:
FILES
/etc/passwd
User account information.
/etc/shadow
Secure user account information.
EXIT VALUES
The chage command exits with the following values:
0
success
1
permission denied
2
invalid command syntax
15
can't find the shadow password file
SEE ALSO passwd(5), shadow(5).
shadow-utils 4.1.5.1 05/25/2012 CHAGE(1)