I have been researching to obtain SSL certification expiry for most of our webistes. For some cases, some hosts where not directly accessible so i finally got a solution working with curl using my proxy. This lists the expiry date which i'm finally looking for.
The next step is to try to find a way to get notified 5 days before that date (no emails).
First thoughts are to extract the date using awk/sed from the above result and convert it to epoch:
Then i was thinking to somehow subtract this date to 5 days ago and convert it to epoch time. With both values in hand i subtract and the difference will be the said threshold. if less then, it means less then 5 days prior to expiry.
However i don't see how we can get a GIVEN date and subtract.
Do you have some thoughts or maybe other ideas?
Hi,
Anybody knows how to get what date was 28 days ago of the current system date through UNIX script.
Ex : - If today is 28th Mar 2010 then I have to delete the files which arrived on 1st Mar 2010, (15 Replies)
How could I using the following example, change it to show 2 days ago within the same time frame 0600 AM to 0600 AM
let foo=`date "+(1%H-106)*60+1%M-100"` bar=foo+1440
find . -mmin +$foo -mmin -$bar | tr -s '/','-' '^' | cut -f2,3 -d"^" | tr -s '^' ' ' |
Please use code tags (7 Replies)
Hi
I have shell script and I am facing the below issue to integrate the date calculation to the the script.
If I give the $1 as the date(20110701) then I need to get the 7 days ago date for the same format.(20110624).
At first I thought its a simple one to handle and I did a search in the... (10 Replies)
Hi,
I have one .csv file. I have 2 date columns present in file, column 2 and column 3.
I need to calculate how many days exist between 2 dates.
I am trying to subtract date column 2 from date column 3.
Eg: my file look likes
s.no, Start_date,End_Date
1, 7/29/2012,10/27/2012
2,... (9 Replies)
Hi,
Can you please let me know code for the below (in korn shell)
a) Subtract month(s) from given date
b) Subtract day(s) from give date
c) Subtract month(s) from given timestamp
d) Subtract day(s) from give timestamp (1 Reply)
current date command runs well
awk -v t="$(date +%Y-%m-%d)" -F "'" '$1 < t' myname.dat
subtract 30 days fails
awk -v t="$(date --date="-30days" +%Y-%m-%d)" -F "'" '$1 < t' myname.dat
awk command in hp unix subtract 30 days automatically from current date without date illegal option error... (20 Replies)
Discussion started by: kmarcus
20 Replies
LEARN ABOUT DEBIAN
mojo::date
Mojo::Date(3pm) User Contributed Perl Documentation Mojo::Date(3pm)NAME
Mojo::Date - HTTP 1.1 date container
SYNOPSIS
use Mojo::Date;
my $date = Mojo::Date->new(784111777);
my $http_date = $date->to_string;
$date->parse('Sun, 06 Nov 1994 08:49:37 GMT');
my $epoch = $date->epoch;
DESCRIPTION
Mojo::Date implements HTTP 1.1 date and time functions according to RFC 2616.
Sun, 06 Nov 1994 08:49:37 GMT ; RFC 822, updated by RFC 1123
Sunday, 06-Nov-94 08:49:37 GMT ; RFC 850, obsoleted by RFC 1036
Sun Nov 6 08:49:37 1994 ; ANSI C's asctime() format
ATTRIBUTES
Mojo::Date implements the following attributes.
"epoch"
my $epoch = $date->epoch;
$date = $date->epoch(784111777);
Epoch seconds.
METHODS
Mojo::Date inherits all methods from Mojo::Base and implements the following new ones.
"new"
my $date = Mojo::Date->new;
my $date = Mojo::Date->new($string);
Construct a new Mojo::Date object.
"parse"
$date = $date->parse('Sun Nov 6 08:49:37 1994');
Parse date in one of the following formats.
- Epoch format(784111777)
- RFC 822/1123 (Sun, 06 Nov 1994 08:49:37 GMT)
- RFC 850/1036 (Sunday, 06-Nov-94 08:49:37 GMT)
- ANSI C asctime() (Sun Nov 6 08:49:37 1994)
"to_string"
my $string = $date->to_string;
Render date suitable for HTTP 1.1 messages.
SEE ALSO
Mojolicious, Mojolicious::Guides, <http://mojolicio.us>.
perl v5.14.2 2012-09-05 Mojo::Date(3pm)