Concatenate integer and space/newline for cout in C++
I'm trying to print out integers and space/newline for a nicer output, for example, every 20 integers in a row with ternary operator.
In C I could do it with:
but could not figure out the equivalent in C++:
Can anyone correct my code for the right trick?
Thanks!
Hi,
I downloaded the latest sparc ver of sol10, tried to concatenate the files and encounter error: Not enough space on the disk. Tried from both sol10 x86 and winxp.
command used:
UNIX: cat file1 file2 file3 file4 file5 > file.iso
DOS: copy /b file1 + file2 + file3 + file4 + file5 file.iso... (3 Replies)
Hi , i want to Concatenate a string and use the following code
str="i"
str="$str am \n"
str="$str a \n"
str="$str boy \n"
echo $str
I want to ouput this
i
am
a
boy
However it outputs
i am \n a \n boy \n (3 Replies)
Hi,
I have a problem where some of the records I need to process have the first address field as something like "10Walpole Street" where obviously I want it to be "10 Walpole Street". I know I need to somehow separate out the integer and probably form a new string variable, but I just don't... (5 Replies)
Input:
--------------------------
123asd 456sdasda 789a
-------------------------
output wanted:
---------------------
123asd
456sdasda
789a
----------------------
I want this by sed in simple way
please help (I know by: tr ' ' '\n' < inputfile )I want it by sed only (5 Replies)
Can someone help me on this. I have a file that has a long line just like below. The long line keeps on being truncated to the next line (new line + space) for some reason. Basically, I just need to remove this problem. Hope somebody can help! Thanks!
INPUT FILE:
structuralObjectClass:... (4 Replies)
Hi All,I am facing the below problem I have set a variable:
a=`cat a.txt| grep "mad" | cut -c 30-50`the output is coming
echo $a1
10 Mad300 3215however the actual ouput is
1.10 Mad300 3215There are 4spaces between 300 and 3215 so if i do:
echo "$a" I am getting correct output:
1.10... (3 Replies)
I am having a peculiar problem. First I run the code below to append 0 at the start of each line in some hundreds of files that I have in a directory. These files have each word in a newline.
for f in *.dat; do
echo "0" > tmpfile
cat $f >> tmpfile
mv tmpfile $f
done
Then I run this... (7 Replies)
Hello
I have had a requirement where I need to move data to a new line based on a text .So basically as soon as it encounters :61: it should move to a new line
Source Data :
:61:D100,74NCH1 :61:D797,50NCH2 :61:D89,38NCHK2 :61:D99,38NCHK12 :61:D79,38NCHK22 :61:D29,38NCHK5
Target Data... (11 Replies)
Discussion started by: kamijia83
11 Replies
LEARN ABOUT DEBIAN
devel::refcount
Devel::Refcount(3pm) User Contributed Perl Documentation Devel::Refcount(3pm)NAME
"Devel::Refcount" - obtain the REFCNT value of a referent
SYNOPSIS
use Devel::Refcount qw( refcount );
my $anon = [];
print "Anon ARRAY $anon has " . refcount($anon) . " reference
";
my $otherref = $anon;
print "Anon ARRAY $anon now has " . refcount($anon) . " references
";
DESCRIPTION
This module provides a single function which obtains the reference count of the object being pointed to by the passed reference value.
FUNCTIONS
$count = refcount($ref)
Returns the reference count of the object being pointed to by $ref.
COMPARISON WITH SvREFCNT
This function differs from "Devel::Peek::SvREFCNT" in that SvREFCNT() gives the reference count of the SV object itself that it is passed,
whereas refcount() gives the count of the object being pointed to. This allows it to give the count of any referent (i.e. ARRAY, HASH,
CODE, GLOB and Regexp types) as well.
Consider the following example program:
use Devel::Peek qw( SvREFCNT );
use Devel::Refcount qw( refcount );
sub printcount
{
my $name = shift;
printf "%30s has SvREFCNT=%d, refcount=%d
",
$name, SvREFCNT($_[0]), refcount($_[0]);
}
my $var = [];
printcount 'Initially, $var', $var;
my $othervar = $var;
printcount 'Before CODE ref, $var', $var;
printcount '$othervar', $othervar;
my $code = sub { undef $var };
printcount 'After CODE ref, $var', $var;
printcount '$othervar', $othervar;
This produces the output
Initially, $var has SvREFCNT=1, refcount=1
Before CODE ref, $var has SvREFCNT=1, refcount=2
$othervar has SvREFCNT=1, refcount=2
After CODE ref, $var has SvREFCNT=2, refcount=2
$othervar has SvREFCNT=1, refcount=2
Here, we see that SvREFCNT() counts the number of references to the SV object passed in as the scalar value - the $var or $othervar
respectively, whereas refcount() counts the number of reference values that point to the referent object - the anonymous ARRAY in this
case.
Before the CODE reference is constructed, both $var and $othervar have SvREFCNT() of 1, as they exist only in the current lexical pad. The
anonymous ARRAY has a refcount() of 2, because both $var and $othervar store a reference to it.
After the CODE reference is constructed, the $var variable now has an SvREFCNT() of 2, because it also appears in the lexical pad for the
new anonymous CODE block.
PURE-PERL FALLBACK
An XS implementation of this function is provided, and is used by default. If the XS library cannot be loaded, a fallback implementation in
pure perl using the "B" module is used instead. This will behave identically, but is much slower.
Rate pp xs
pp 225985/s -- -66%
xs 669570/s 196% --
SEE ALSO
o Test::Refcount - assert reference counts on objects
AUTHOR
Paul Evans <leonerd@leonerd.org.uk>
perl v5.14.2 2011-11-15 Devel::Refcount(3pm)