A way to print only part of directory path Post: 303011584

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getting the path part of an argument

Seems I'm inundating this forum with questions, but anyway: I am writing a script that should accept one and only one argument when called. That argument should designate a file, either with path/filename or just filename. Now to the difficult bit: I want to figure out a way to store...

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How do I get awk to print a " in it's print part?

The line is simple, use " '{ print $1"]"$2"\"$3THE " NEEDS TO GO HERE$4 }' I've tried \", "\, ^" and '"" but none of it works. What am I missing? Putting in the [ between $1 and $2 works fine, I just need to do the same with a ". Thanks.

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Hi I am trying to use sed to retrieve part of my html file's path. I am having a hard time getting what I want. Could someone give me some help? I want to retrieve the section after html and before the file name For example if I have the following, ...

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I'm trying to clean up my samba share and need to print the found file or print the path of the image it tried to searched for. So far I have this but can't seem to get the logic right. Can anyone help point me in the right direction? for FILE in `cat list`; do if ; then ...

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Print directory name along with their path

Can any one tell me that how can i print all directory with their path in a given parent directory. i.e. parent directory /home/usr/ Now this shoe directory may contain sevral directory /home/usr dir1/ dir1.1/ dir1.2/ dir2 dir2.1/ dir2.2/ ...

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Hi, I have a file abcd.txt which has contents in the form of full path file names i.e. $home> vi abcd.txt /a/b/c/r1.txt /q/w/e/r2.txt /z/x/c/r3.txt Now I want to retrieve only the directory path name for each row i.e /a/b/c/ /q/w/e/ How to get the same through shell script?...

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hi, i have a directory at /path/unix with the following files 1.txt 2.txt 3.txt 4.txt I want to make another file called filenames.txt at a different location called /path/home. So, my output file would be /path/home/filenames.txt with contents /path/unix/1.txt...

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Extract directory name from the full directory path in UNIX using shell scripting

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Convert Relative path to Absolute path, without changing directory to the file location.

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LEARN ABOUT LINUX

getbuildlog

GETBUILDLOG(1)                                                General Commands Manual                                               GETBUILDLOG(1)

NAME

       getbuildlog - download build logs from Debian auto-builders

SYNOPSIS

       getbuildlog package [version-pattern] [architecture-pattern]

DESCRIPTION

       getbuildlog downloads build logs of package from Debian auto-builders. It downloads build logs of all versions and for all architectures if
       version-pattern and architecture-pattern are not specified or empty, otherwise only build logs whose  versions  match  version-pattern  and
       build  logs  whose  architectures  match  architecture-pattern will be downloaded. The version and architecture patterns are interpreted as
       extended regular expressions as described in grep(1).

       If version-pattern is "last" then only the logs for the most recent version of package found on buildd.debian.org will be downloaded.

       If version-pattern is "last-all" then the logs for the most recent version found on each build log index will be downloaded.

OPTIONS

       -h, --help
              Show usage information and examples.

       -V, --version
              Show version and copyright information.

EXAMPLES

       getbuildlog hello 2.2-1 amd64
              Download amd64 build log for hello version 2.2-1.

       getbuildlog glibc "" mips.*
              Download mips(el) build logs of all glibc versions.

       getbuildlog wesnoth .*bpo.*
              Download all build logs of backported wesnoth versions.

AUTHOR

       Written by Frank S. Thomas <fst@debian.org>.

DEBIAN                                                           Debian Utilities                                                   GETBUILDLOG(1)

10 More Discussions You Might Find Interesting

1. Shell Programming and Scripting

getting the path part of an argument

Discussion started by: ropers

2. Shell Programming and Scripting

How do I get awk to print a " in it's print part?

Discussion started by: LordJezo

3. Shell Programming and Scripting

retrieve part of file path

Discussion started by: tiger66

4. Shell Programming and Scripting

Howto Print File Path or Print the Filename

Discussion started by: overkill