I thought it was obvious that my system is OS X since Apple icon I sticked to the top of my message and besides I indicated at the bottom that my shell is bash 3.2.48.

I have an app whose bundle id contains the word keyword. Also this word is a significant part of all of the files and folders that got installed or created together with the main bundle upon me running and installing the app. On OS X these files can be installed across the entire system (HFS+) beginning with /private/var/db or /private/var/folders, /Library folders and, of course those of ~/Library (plists, cache file, application support folders etc.residing in different places). Unfortunately when searching with the most basic form of find (find / -name keyword) I got a bunch of pathnames that are references to web-entries, containing the keyword whose practical value is negligible. I need to filter out those and have only those files and folders that belong to the items created by the app proper. They contain either keyword or KEYWORD. That's why I used alternation operator | with the items grouped inside parentheses. Since the history of web-search contains the same keyword that is a part of pathnames each containing the name of one of these web-browsers I wanted to skip every pathname containing the respective name of any of the browsers. As browser's name
appears both in the pathname of some of the browser's folders (like /Users/myuser/Library/Safari, /Users/myuser/Library/Cache/Safari, /Users/myuser/Library/Preferences/com.apple.Safari.plist etc., the same's true for Firefox containing sometimes "mozilla" or "Mozilla" in its folder names too) and its regular files of smaller size, I tried to form the regular expression meeting these criteria with the alternation operator as well with regards to case sensitivity (find all patterns matching the keyword irrespective of the case; ignore all the pathnames containing the name of one of the browsers included in the parentheses on the alternative basis).

The thing is I'm confused about purpose and meaning of the syntax that looks similar: do I need to use -exec find, -exec grep (but then in the latter case I need the option -E because | is Extended Set)? Or maybe pipe to grep instead?
I noticed two options to grep: -L, --files-without-match
What does "from which no output would normally have been printed." mean?

"The scanning will stop on the first match" - Match to what? And if it will stop how do I get the output.

Furthermore, -l, --files-with-matches
"from which output would normally have been printed"?

I used --directories=skip because
,
I thought the directories whose pathnames contains names of these browsers would be skipped.

Let's say I write

Code:

find -E /" -regex '.*/(Safari|[Oo]pera|Firefox|[Mm]ozilla)/.*' -prune -o -exec grep -iE './keyword/.*' {} ;

1. IF the syntax itself is correct then I have no clue what to expect. I cannot be sure which option to pick since I don't understand this:

from man find on -exec utility [argument ...]

What the current file is? What's the deal with ; as a control operator? What does it control?
On the other hand

from man find on -exec utility [argument ...] {} +
``{}'' is replaced with as many pathnames as possible for each invocation of utility .

How would you compose the line to achieve the task? Because all the explanations are crystal clear while they manipulate simple examples. That one is more advance, I dare to think.

Moderator's Comments:

Please wrap all code, files, input & output/errors in CODE tags. Please wrap code/data snippets inside a paragraph with ICODE tags. Please wrap quoted text in QUOTE tags. It makes them far easier to read and preserves spacing for indenting or fixed width data.