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Top Forums Shell Programming and Scripting Using CURL command with special characters in URL Post 303009447 by Don Cragun on Thursday 14th of December 2017 01:48:40 PM
Old 12-14-2017
Instead of looking for characters that are special to the shell and individually escaping them, it might be simpler to just quote the argument you're passing to curl:
Code:
curl -X GET "https://www.example.com/?sample=name&id=1001"

 

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curl_easy_escape(3)						  libcurl Manual					       curl_easy_escape(3)

NAME
curl_easy_escape - URL encodes the given string SYNOPSIS
#include <curl/curl.h> char *curl_easy_escape( CURL *curl, const char *string , int length ); DESCRIPTION
This function converts the given input string to a URL encoded string and returns that as a new allocated string. All input characters that are not a-z, A-Z, 0-9, '-', '.', '_' or '~' are converted to their "URL escaped" version (%NN where NN is a two-digit hexadecimal number). If length is set to 0 (zero), curl_easy_escape(3) uses strlen() on the input string to find out the size. You must curl_free(3) the returned string when you're done with it. AVAILABILITY
Added in 7.15.4 and replaces the old curl_escape(3) function. RETURN VALUE
A pointer to a zero terminated string or NULL if it failed. EXAMPLE
CURL *curl = curl_easy_init(); if(curl) { char *output = curl_easy_escape(curl, "data to convert", 15); if(output) { printf("Encoded: %s ", output); curl_free(output); } } SEE ALSO
curl_easy_unescape(3), curl_free(3), RFC3986 libcurl 7.54.0 February 03, 2016 curl_easy_escape(3)
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