Hello,
does somebody knows about a function that would convert a date like:
YYMMDD into a date like YYYY-MM-DD ?
Thank you for your ideas
:) (9 Replies)
hi,
i have a file in which i get date format as 22/APR/2010...
now i want the date format to be in 22-04-2010
if the month changes to may the file should also have 05 as month....
pls help (3 Replies)
Hi All,
Can someone please let me know how can i convert the date format in unix as follow:
From: 24 Oct 2011
i.e $(date +'%d %b %Y')
To: 111024
i.e $(date +%y%m%d)
Thanks in advance (3 Replies)
Looking for some help and usually when I do a search this site comes up. Hopefully someone can give me a little direction as to how to use one of these two commands to achieve what I'm trying to do.
What am I trying to do?
I need to take the time value in epoch format returned from the... (5 Replies)
I have below date format in a CSV file. (dd/mm/yyyy)
Ex Input:
9/8/2013
Need to convert it into below format (yyyymmdd ) and redirect to new file.
Ex Output:
20130809
How do I use awk here to change the format and if leading 0 (zero) is not then add it.
Please help. Thanks. (8 Replies)
hi i want to convert date procured from sone operation which will be in 24hr format to 12 hr format displaying AM and PM
# date -d @1362545068
Tue Mar 5 23:44:28 EST 2013
#
this Tue Mar 5 23:44:28 EST 2013
i want to convert it so that output is as below
Tue... (2 Replies)
Hello ,
I have a record in below format
Hostname | Query: 0 | Release: 0 | files: 2 | Files_examined: 2 | SET timestamp=1396778638; | select * from test
I need output in below format
Hostname | 0 | 0 | 2 | 2 | 04/06/2014|03:03:58 | select * from test
I was able to get above output... (1 Reply)
Hi,
i have to check the file whether it is created today. here is the ls -l o/p
-rw-r----- 20000 50000 130 Dec 12 10:21 file.txt
im able to check if file is created today or not if the timestamp is in 2014-12-12 format by comparing $(date +Y-%m-%d)
but stuckup as it is of format Dec 12... (6 Replies)
I have a script below and wanted to change the output into three different file format (3 separate script)
#!bin/bash
#input file format postwrf_d01_20131206_0600_f08400.grb2
#postwrf_d01_YYYYMMDD_ZZZZ_f0HHHH.grb2
#zzzz= 0000,0600,1200,1800 (in UTC)
#HHHH=00000,00600,01200,01800 ..ect (in... (1 Reply)
Discussion started by: cumulus_255
1 Replies
LEARN ABOUT PHP
dbase_replace_record
DBASE_REPLACE_RECORD(3) 1 DBASE_REPLACE_RECORD(3)dbase_replace_record - Replaces a record in a databaseSYNOPSIS
bool dbase_replace_record (int $dbase_identifier, array $record, int $record_number)
DESCRIPTION
Replaces the given record in the database with the given data.
PARAMETERS
o $dbase_identifier
- The database link identifier, returned by dbase_open(3) or dbase_create(3).
o $record
- An indexed array of data. The number of items must be equal to the number of fields in the database, otherwise
dbase_replace_record(3) will fail.
Note
If you're using dbase_get_record(3) return value for this parameter, remember to reset the key named deleted.
o $record_number
- An integer which spans from 1 to the number of records in the database (as returned by dbase_numrecords(3)).
RETURN VALUES
Returns TRUE on success or FALSE on failure.
EXAMPLES
Example #1
Updating a record in the database
<?php
// open in read-write mode
$db = dbase_open('/tmp/test.dbf', 2);
if ($db) {
// gets the old row
$row = dbase_get_record_with_names($db, 1);
// remove the 'deleted' entry
unset($row['deleted']);
// Update the date field with the current timestamp
$row['date'] = date('Ymd');
// Replace the record
dbase_replace_record($db, $row, 1);
dbase_close($db);
}
?>
SEE ALSO dbase_add_record(3), dbase_delete_record(3).
PHP Documentation Group DBASE_REPLACE_RECORD(3)