Hello,
does somebody knows about a function that would convert a date like:
YYMMDD into a date like YYYY-MM-DD ?
Thank you for your ideas
:) (9 Replies)
hi,
i have a file in which i get date format as 22/APR/2010...
now i want the date format to be in 22-04-2010
if the month changes to may the file should also have 05 as month....
pls help (3 Replies)
Hi All,
Can someone please let me know how can i convert the date format in unix as follow:
From: 24 Oct 2011
i.e $(date +'%d %b %Y')
To: 111024
i.e $(date +%y%m%d)
Thanks in advance (3 Replies)
Looking for some help and usually when I do a search this site comes up. Hopefully someone can give me a little direction as to how to use one of these two commands to achieve what I'm trying to do.
What am I trying to do?
I need to take the time value in epoch format returned from the... (5 Replies)
I have below date format in a CSV file. (dd/mm/yyyy)
Ex Input:
9/8/2013
Need to convert it into below format (yyyymmdd ) and redirect to new file.
Ex Output:
20130809
How do I use awk here to change the format and if leading 0 (zero) is not then add it.
Please help. Thanks. (8 Replies)
hi i want to convert date procured from sone operation which will be in 24hr format to 12 hr format displaying AM and PM
# date -d @1362545068
Tue Mar 5 23:44:28 EST 2013
#
this Tue Mar 5 23:44:28 EST 2013
i want to convert it so that output is as below
Tue... (2 Replies)
Hello ,
I have a record in below format
Hostname | Query: 0 | Release: 0 | files: 2 | Files_examined: 2 | SET timestamp=1396778638; | select * from test
I need output in below format
Hostname | 0 | 0 | 2 | 2 | 04/06/2014|03:03:58 | select * from test
I was able to get above output... (1 Reply)
Hi,
i have to check the file whether it is created today. here is the ls -l o/p
-rw-r----- 20000 50000 130 Dec 12 10:21 file.txt
im able to check if file is created today or not if the timestamp is in 2014-12-12 format by comparing $(date +Y-%m-%d)
but stuckup as it is of format Dec 12... (6 Replies)
I have a script below and wanted to change the output into three different file format (3 separate script)
#!bin/bash
#input file format postwrf_d01_20131206_0600_f08400.grb2
#postwrf_d01_YYYYMMDD_ZZZZ_f0HHHH.grb2
#zzzz= 0000,0600,1200,1800 (in UTC)
#HHHH=00000,00600,01200,01800 ..ect (in... (1 Reply)
Discussion started by: cumulus_255
1 Replies
LEARN ABOUT SUSE
unbuffer
UNBUFFER(1) General Commands Manual UNBUFFER(1)NAME
unbuffer - unbuffer output
SYNOPSIS
unbuffer program [ args ]
INTRODUCTION
unbuffer disables the output buffering that occurs when program output is redirected from non-interactive programs. For example, suppose
you are watching the output from a fifo by running it through od and then more.
od -c /tmp/fifo | more
You will not see anything until a full page of output has been produced.
You can disable this automatic buffering as follows:
unbuffer od -c /tmp/fifo | more
Normally, unbuffer does not read from stdin. This simplifies use of unbuffer in some situations. To use unbuffer in a pipeline, use the
-p flag. Example:
process1 | unbuffer -p process2 | process3
CAVEATS
unbuffer -p may appear to work incorrectly if a process feeding input to unbuffer exits. Consider:
process1 | unbuffer -p process2 | process3
If process1 exits, process2 may not yet have finished. It is impossible for unbuffer to know long to wait for process2 and process2 may
not ever finish, for example, if it is a filter. For expediency, unbuffer simply exits when it encounters an EOF from either its input or
process2.
In order to have a version of unbuffer that worked in all situations, an oracle would be necessary. If you want an application-specific
solution, workarounds or hand-coded Expect may be more suitable. For example, the following example shows how to allow grep to finish pro-
cessing when the cat before it finishes first. Using cat to feed grep would never require unbuffer in real life. It is merely a place-
holder for some imaginary process that may or may not finish. Similarly, the final cat at the end of the pipeline is also a placeholder
for another process.
$ cat /tmp/abcdef.log | grep abc | cat
abcdef
xxxabc defxxx
$ cat /tmp/abcdef.log | unbuffer grep abc | cat
$ (cat /tmp/abcdef.log ; sleep 1) | unbuffer grep abc | cat
abcdef
xxxabc defxxx
$
BUGS
The man page is longer than the program.
SEE ALSO
"Exploring Expect: A Tcl-Based Toolkit for Automating Interactive Programs" by Don Libes, O'Reilly and Associates, January 1995.
AUTHOR
Don Libes, National Institute of Standards and Technology
1 June 1994 UNBUFFER(1)