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Full Discussion: Inputs argument for sh -c
Top Forums Shell Programming and Scripting Inputs argument for sh -c Post 303008439 by Corona688 on Friday 1st of December 2017 10:23:21 AM
Old 12-01-2017
Quote:
Originally Posted by puertas12
Can someone give a source to start digging on this?
Advanced Bash-Scripting Guide

Quote:
Furthermore. Can someone clarify the following:
$0 $1 $2 ... After the sh -c
They are not the same $0 $1 $2 variables as your own shell. They are in single quotes:
Code:
'echo "Dumping file: $2" >> "$1"; w3m "$2" >> "$1" 2>&1'

...so they are passed into sh -c unparsed, for it to handle.

I have my doubts about them too.
Quote:
$1: name of the log file Why ??? From where is taken
Nowhere, I think. There is a different form of shell code which I think they tried to adapt from:

Code:
echo 'echo arg1 $1 arg2 $2 arg3 $3 arg4 $4' | sh -s -- a b c d

This runs with the result:
Code:
arg1 a arg2 b arg3 c arg4 d

...But it runs code from standard input, not -c, so can't be used with xargs.

Someone tried to adapt that into a form suitable for xargs and didn't know what those arguments were for, so left them dangling.
 

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