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Operating Systems Linux How to print full path name along with file extension? Post 303007316 by rbatte1 on Wednesday 15th of November 2017 08:13:57 AM
Old 11-15-2017
Bash variable substitution option

Even this could do the trick:-
Code:
#!/bin/bash

while read full_filename
do
   directory="${full_filename%/*}/"
   filenames="*.${full_filename##*.}"
   echo "${directory}${filenames}"
done < <(find /abc -type f) | sort -u

I'm not saying it's pretty; it is just another alternative if that suits your coding style. It uses very few processes, which might be important to performance if you have lots of files.


Assuming that this is to be used by something else that will expand it all again, is there a reason not to build this process into that code and remove the need to juggle it all and then re-expand?

Can you elaborate?



Robin

Last edited by rbatte1; 11-15-2017 at 09:18 AM.. Reason: Smartened code
This User Gave Thanks to rbatte1 For This Post:
 

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NAMESPACE(6)							   Games Manual 						      NAMESPACE(6)

NAME
namespace - name space description file DESCRIPTION
Namespace files describe how to construct a name space from scratch, an operation normally performed by the newns subroutine (see auth(2)) which is typically called by init(8). Each line specifies one name space operation. Spaces and tabs separate arguments to operations; no quotes or escapes are recognized. Blank lines and lines with # as the first non-space character are ignored. Environment variables of the form $name are expanded within arguments, where name is a UTF string terminated by white space, a /, or a $. The known operations and their arguments are: mount [-abc] servename old [spec] Mount servename on old. bind [-abc] new old Bind new on old. import [-abc] host "[remotepath]mountpoint Import remotepath from machine server and attach it to mountpoint. cd dir Change the working directory to dir. The options for bind, mount, and import are interpreted as in bind(1) and import(4). SEE ALSO
bind(1), namespace(4), init(8) NAMESPACE(6)
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