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Top Forums Shell Programming and Scripting Problem wth spec chars in script Post 303006271 by elxa1 on Monday 30th of October 2017 03:40:28 PM
Old 10-30-2017
Quote:
Originally Posted by jim mcnamara
Your answer is somewhat evasive.

Two ways:
1. use the printf method to embed punctuation and other odd characters. Unless you are using windows do not put \r in anything. expect gets a return from bash reading the script -- and it is a newline, \n

2. you can escape characters ( \ escape in front of each character, so \\ is read by the shell as a backslash, not escape). The shell takes them as literal characters, not some shell command -- example \*\# is an asterisk and an octothorpe (pound sign). Not a wild card and not a start of a comment.
Thank You Jim for your help - and sorry for my late reply. The problem is still actual for me.

So, I suppose, that only proper way for me will be the 1st method. Due to diversity of the passkeys it would be easier than putting backslashes in 2000-marks passkey's for example. The lenght of the keys can differ, and the special chars qty is also random.

About the method you mentioned:

1. I would like to use only in linux, and on linux I also can prepare passlist (unix-type line endings and non viible characters on passlist).

2. If that method (printf) could help - maybe 'expect' will not be essential?

I have tried using expect due to problems with using 7z x -p$klucz (or $passkey) archive.7z
The $ mark is only for calling a variable. That is possible, that on the begginning will be Dollar sign - $ .

Maybe your solution would allow me to use passkeys without bash-processing it in native 7z commands? So, if I can use it as a full text in script - 7z x -p$passkeyfromprintf

Unfortunately - I am starting with bash programming - and I really do not have idea how to use your snippet. Would you like to show me any example how to start using this ?


So, if I would use it my simpler script: (could you please help me with that one?)
"7z t" - 7z TEST, which wll exit when the passkey is bad.

Code:
2var=$(printf "%s%c" "\$klucz" 13)
while read $klucz 
do  7z t -p$2var archive.7z
echo $2var
done<passkeylist.txt

Is that should work?
regards
 

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uudemon(4)						     Kernel Interfaces Manual							uudemon(4)

NAME
uudemon.admin, uudemon.cleanu, uudemon.hour, uudemon.poll - Administrative shell scripts for polling remote systems, cleaning up spool directories, reporting status to the system administrator, and routine invocations of the uuxqt and uusched daemons SYNOPSIS
These shell scripts reside in the following directory: /usr/lib/uucp DESCRIPTION
All the scripts can be run from the command line or can be run automatically by the cron daemon. To automatically run the scripts, remove the comment character (#) from the beginning of the relevant line in the /var/spool/cron/crontabs/uucp file. This script reports status to the system administrator. It issues the uustat command to find out the status of uucp jobs. It mails the results to the uucp login ID. The script may be modified to send mail to any login ID such as the uucp administrative login ID (uucpa) or root. This script cleans up the /var/spool/uucp and /var/spool/uucppublic directories by running the uucleanup command. The uucleanup com- mand is run with the following parameters: -C7, -D7, X2, -o2, -W1. This script runs the uusched and uuxqt daemons in the background. This script polls the systems listed in the /usr/lib/uucp/Poll file. The uudemon.poll script should be scheduled before the uudemon.hour script. This allows uudemon.poll to create any command files before cron runs the uudemon.hour script. FILES
Contains the uudemon.admin, uudemon.cleanu, uudemon.hour and uudemon.poll files. Contains the uucp file. RELATED INFORMATION
Commands: cron(8), uucleanup(8), uusched(8), uuxqt(1) Files: /usr/lib/uucp delim off uudemon(4)
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