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Top Forums Shell Programming and Scripting Variable loses value outside loop Post 303004535 by mohtashims on Wednesday 4th of October 2017 07:08:03 AM
Old 10-04-2017
RedHat

Quote:
Originally Posted by RudiC
Try setting the lastpipe option in bash



I think ksh operates like this per default...
I m trying this option for a solution.

Code:
#!/bin/bash
shopt -s lastpipe

However, I get the below error.

Code:
./run.sh: line 2: shopt: lastpipe: invalid shell option name

My bash version is

Code:
bash-3.2$ bash --version
GNU bash, version 3.2.57(1)-release (sparc-sun-solaris2.10)
Copyright (C) 2007 Free Software Foundation, Inc.


Last edited by mohtashims; 10-04-2017 at 08:24 AM..
 

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