In my bash script I want to add a code which remove all entries older than x days.
To simplify this problem, I have divided into 3 parts. (2 parts are done looking answer for 3rd part.)
To find the latest log date - Done Latest_Time=`find . -name '*.tps' -exec sed '/endTime/!d; s/{//; s/,.*//' {} + | sort -r | head -1 | cut -d: -f2` #latest epoch time
evaluate earliest epoch time. (All entries before this epoch time should be deleted) - Done Earliest_Time=`Latest_Time-(86400000*$No_OF_DAYS)` #earliest epoch time
delete all log entries older than evaluated earliest time.
PS:
there are multiple files and distributed in different sub folders.
All files having extension as ".tps".
time is in epoch format. endTime will be considered for calculations.("endTime":1488902735220)
Problem: Now I am looking for command which delete all the entries which is older/lesses than earliest epoch time. In above example 1st line should be deleted.
Any help/suggestions are appreciated. Thank you
Last edited by rbatte1; 09-29-2017 at 10:15 AM..
Reason: Set up formatted lists and added ICODE tags where appropriate
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09-29-2017
