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Top Forums UNIX for Beginners Questions & Answers awk function to remove lines that contain contents of another file Post 303003745 by MadeInGermany on Wednesday 20th of September 2017 01:52:39 AM
Old 09-20-2017
I do not understand the ! and ++ in {! arr[$0]++; next}
Replace by {arr[$1]; next}. Not storing a value in the array saves sone memory! $1 strips spaces, can make sense if there is invisible trailing space (and embedded spaces wouldn't work anyway when later comparing with $1). The next jumps to the next cycle, no need for checking the FILENAME again. {print $0} is a default action if there is just a condition.
Code:
awk ' FILENAME=="reference.txt" {arr[$1]; next}  # create an array without values 
        !($1 in arr)' reference.txt inputfile > outputfile

 

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GREP(1) 						      General Commands Manual							   GREP(1)

NAME
grep - search a file for lines containing a given pattern SYNOPSIS
grep [-elnsv] pattern [file] ... OPTIONS
-e -e pattern is the same as pattern -c Print a count of lines matched -i Ignore case -l Print file names, no lines -n Print line numbers -s Status only, no printed output -v Select lines that do not match EXAMPLES
grep mouse file # Find lines in file containing mouse grep [0-9] file # Print lines containing a digit DESCRIPTION
Grep searches one or more files (by default, stdin) and selects out all the lines that match the pattern. All the regular expressions accepted by ed and mined are allowed. In addition, + can be used instead of * to mean 1 or more occurrences, ? can be used to mean 0 or 1 occurrences, and | can be used between two regular expressions to mean either one of them. Parentheses can be used for grouping. If a match is found, exit status 0 is returned. If no match is found, exit status 1 is returned. If an error is detected, exit status 2 is returned. SEE ALSO
cgrep(1), fgrep(1), sed(1), awk(9). GREP(1)
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