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Top Forums Shell Programming and Scripting Zipping contents without the actual directory Post 303003349 by bakunin on Wednesday 13th of September 2017 01:07:40 AM
Old 09-13-2017
Quote:
Originally Posted by paul1234
Hi ,
I want to zip files present in the directories listed under a parent directory without zipping the directory itself
You haven't told us which OS you are using:

Code:
find <startdir> -type d -exec /path/to/zip {} {}/* \;

Notice, that some versions of the find-command do not allow for multiple instances of the {}-macro and because i do not know which one you are using you will have to find out if yours does or doesn't. In the latter case put the zip-command into a small script to which you pass the {} as argument and call that from the find-command.

I hope this helps.

bakunin
 

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ZIPMERGE(1)						      General Commands Manual						       ZIPMERGE(1)

NAME
zipmerge - merge zip archives SYNOPSIS
zipmerge [-DhIiSsV] target-zip source-zip Op source-zip ... DESCRIPTION
zipmerge merges the source zip archives source-zip into the target zip archive target-zip. By default, files in the source zip archives overwrite existing files of the same name in the target zip archive. Supported options: -D Ignore directory components in file name comparisons. -h Display a short help message and exit. -I Ignore case in file name comparisons -i Ask before overwriting files. See also -s. -S Do not overwrite files that have the same size and CRC32 in both the source and target archives. -s When -i is given, do not before overwriting files that have the same size and CRC32. -V Display version information and exit. EXIT STATUS
zipmerge exits 0 on success and 1 if an error occurred. SEE ALSO
zipcmp(1), ziptorrent(1), libzip(3) AUTHORS
Dieter Baron <dillo@giga.or.at> and Thomas Klausner <tk@giga.or.at> NiH June 4, 2008 ZIPMERGE(1)
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