This statement means that if there is no gene2 then there cannot be a gene3 read:
When you use the read statement you have to have all fields there in order to get gene3.
Otherwise gene3 is an "empty" variable. Or the same can happen for gene2.
You can create dummy values for those variables if they are empty, but since you have a separate script processing things that could affect the output of that script.
Try creating an intermediate file with dummy variables, let's use the word 'dummy' for the values of empties. This is awk, the output file will be called tmp.tmp which is what your script will have to use for input.
This could also be set up writing to a pipe which your existing script reads.
So the last 2 fields in tmp.tmp can be a real value, or just fiber filler: "dummy", but there will always be 8 fields. The last two fields cannot be blank or bash will not read them into a variable.
If no arguments are entered I wanna be able to read 2 arguments, i have done like this but it doesnt work:
x=0
until #loop starts
do
if ; then
echo No arguments were entered, please enter 2 arguments.
read $1 $2
elif || ; then
echo $#... (0 Replies)
Hi,
I'm trying to write a script that reads filenames from a file and use these filenames in a loop. The filenames are all on one line and the problem is that these filenames have wildcards like * and braces like in them.
Right now what I'm doing is something like this:
echo "reading from... (0 Replies)
Hi.
I have the script shown below. If I execute it form the command line it seems to work properly, but when I fun it using the unix "at" command
"at -m now < ./kill-at-job.sh"
It appears to hang. Below is the script, the input file, and the execution as reported in the e-mail from the "at"... (3 Replies)
i get a name from user first name : last name, in this format. Now i am saving this to a file. what i want is, I do not want to save any name if I already have one entry o that same name..what should i do
for example
user give robert fernandez
this will save in file as robert:fernandez.
if... (5 Replies)
Hi All,
I am trying to read a .csv file which has some 6 columns.
Eg: samp.csv
one, two, three, four
six, seven, eight, nine
I used the following code,
for line in `cat samp.csv`
do
echo "$line"
done
It displays every comma seperated values in each line like,
one,... (1 Reply)
I have a file that has four values on each line and I'd like to give each column a variable name and then use those values in each step of a loop. In bash, I believe you could use a while loop to do this or possibly a cat command, but I am super new to programming and I'm having trouble decoding... (2 Replies)
I have the following code and I am calling it using
./raytrac.bash -u
and getting problems. For some reason opt_usage is still 0.
opt_usage=0
iarg=0
narg=$#
while (($iarg < $narg))
do
(( iarg = $iarg + 1 ))
arg=$argv
usrInputFlag=`echo $arg | awk '/=/ {print 1}; ! /=/... (22 Replies)
I've a file in linux with following text:
;ip address hostname put-location alt-put-location tftpserver
192.168.1.1 r01-lab1-net /mnt/nas1/fgbu/ /opt/fgbu/devicebackup 192.168.1.254Now I want to read these values and assign them to particular variables... (6 Replies)
Hi all,
Given here under a section of a script I am using.
SIMDIR="/home/Ins/forces"
cd $SIMDIR
for file in `ls *.forces`
do
basename=`echo $file | sed 's/\.*$//'`
extname=`echo $file | sed 's/*\(*\)\.\(.*\)/\2\1/'`
echo "Processing file: "$basename
python convert.py... (4 Replies)
Cope sample1: test.sh
i=0
echo " Outside loop i = $i "
while
do
i=$(( $i + 1))
echo "Inside loop i = $i "
done
echo " Out of loop i is : $i "
When run output :
Outside loop i = 0
Inside loop i = 1
Inside loop i = 2
Inside loop i = 3
Inside loop i = 4
Inside loop i = 5
Inside... (8 Replies)
Discussion started by: Adarshreddy01
8 Replies
LEARN ABOUT PHP
libbash
LIBBASH(7) libbash Manual LIBBASH(7)NAME
libbash -- A bash shared libraries package.
DESCRIPTION
libbash is a package that enables bash dynamic-like shared libraries. Actually its a tool for managing bash scripts whose functions you may
want to load and use in scripts of your own.
It contains a 'dynamic loader' for the shared libraries ( ldbash(1)), a configuration tool (ldbashconfig(8)), and some libraries.
Using ldbash(1) you are able to load loadable bash libraries, such as getopts(1) and hashstash(1). A bash shared library that can be loaded
using
ldbash(1) must answer 4 requirments:
1. It must be installed in $LIBBASH_PREFIX/lib/bash (default is /usr/lib/bash).
2. It must contain a line that begins with '#EXPORT='. That line will contain (after the '=') a list of functions that the library
exports. I.e. all the function that will be usable after loading that library will be listed in that line.
3. It must contain a line that begins with '#REQUIRE='. That line will contain (after the '=') a list of bash libraries that are
required for our library. I.e. every bash library that is in use in our bash library must be listed there.
4. The library must be listed (For more information, see ldbashconfig(8)).
Basic guidelines for writing library of your own:
1. Be aware, that your library will be actually sourced. So, basically, it should contain (i.e define) only functions.
2. Try to declare all variables intended for internal use as local.
3. Global variables and functions that are intended for internal use (i.e are not defined in '#EXPORT=') should begin with:
__<library_name>_
For example, internal function myfoosort of hashstash library should be named as
__hashstash_myfoosort
This helps to avoid conflicts in global name space when using libraries that come from different vendors.
4. See html manual for full version of this guide.
AUTHORS
Hai Zaar <haizaar@haizaar.com>
Gil Ran <ril@ran4.net>
SEE ALSO ldbash(1), ldbashconfig(8), getopts(1), hashstash(1)colors(1)messages(1)urlcoding(1)locks(1)Linux Epoch Linux