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Top Forums Shell Programming and Scripting Scratching my head over old post Post 303003145 by RudiC on Friday 8th of September 2017 04:24:58 AM
Old 09-08-2017
1) awk with RS set to ) doesn't break records at line ends but on occurrences of the RS char / pattern. So, the first record (also referred to as $0 in awk) is
Code:
 process(130

, which is split in two at the field separator FS=\(.
Code:
$0=$2

then overwrites the entire record with its second field, and, because used as an awk-pattern not equal 0 (= TRUE), takes the default action print.

2) Your echotext is corrupted in your post as the second left parenthesis is missing. The sed substitutes the BRE
Code:
^               start of line
.*(             (.) any character (*) zero or more times up to a left parenthesis
\([^)]*\)       first sub-expression (delimited by escaped! parentheses): zero or more non-right-par.
).*(....        next right par. followed by any char zero + times, then left par., then any four chars
\(.*\)          second sub-expr.: any chars zero or more times
).*'            next right par. followed by any char 0+ times, then apostrophe (single quote)
\(.*\)          third sub-expr.: any chars 0+ times
'.*             rest of line starting from apostrophe

by first sub-expr. space second sub-expr. space third sub-expr.
 

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expr(1) 						      General Commands Manual							   expr(1)

Name
       expr - evaluate expressions

Syntax
       expr arg...

Description
       The arguments are taken as an expression.  After evaluation, the result is written on the standard output.  Each token of the expression is
       a separate argument.

       The operators and keywords are listed below.  The list is in order of increasing precedence, with equal precedence operators grouped.

       expr | expr	   Yields the first expr if it is neither null nor 0.  Otherwise yields the second expr.

       expr & expr	   Yields the first expr if neither expr is null or 0.	Otherwise yields 0.

       expr relop expr	   The relop is one of < <= = != >= > and yields 1 if the indicated comparison is true, '0' if false.  The  comparison	is
			   numeric if both expr are integers, otherwise lexicographic.

       expr + expr
	    expr - expr
			   Yields addition or subtraction of the arguments.

       expr * expr
	    expr / expr
	    expr % expr
			   Yields multiplication, division, or remainder of the arguments.

       expr : expr	   The	matching  operator compares the string first argument with the regular expression second argument; regular expres-
			   sion syntax is the same as that of The (...) pattern symbols can be used to select a portion of the  first  argument.
			   Otherwise, the matching operator yields the number of characters matched ('0' on failure).

       ( expr ) 	   parentheses for grouping.

Examples
       The first example adds 1 to the Shell variable a:
       a=`expr $a + 1`
       The second example finds the file name part (least significant part) of the pathname stored in variable a,
       expr $a : '.*/(.*)' '|' $a
       Note the quoted Shell metacharacters.

Diagnostics
       The command returns the following exit codes:

       0    The expression is neither null nor '0'.

       1    The expression is null or '0'.

       2    The expression is invalid.

See Also
       ed(1), sh(1), test(1)

																	   expr(1)
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