Hi All,
I am trying to generate quarter dates with user giving input as begin date and end date. Example: Input by user:
begin_date = "2009-01-01"
end_date = 2010-04-30"
required output:
2009-01-01 2009-03-31 09Q01
2009-04-01 2009-06-30 09Q02
.
.
till
2010-01-01 2010-03-31 10Q01
... (9 Replies)
Hi.,
After retrieving values from DB I have two datestamps in format:
12/01/2010:05:40:00 AM and 12/01/2010:06:00:00 PM.
general time format: MM/DD/YYYY:HH:MM:SS AM or PM
Any quick solution to get the difference of two in the format : 1 day(s) 12:20:00
Thanks., (6 Replies)
Dear Members,
Depending on the current date i should find out the start and end dates of the quarter.
ex: Today date is 14-Nov-2011 then Quarter start date should be Oct 1 2011 and Quarter End date should be Dec 31 2011.
How can i do this?
Thanks
Sandeep (1 Reply)
Hi there,
I have a requirement to append dates going forward to a certain line in a file.
I'm not sure of how to go about this. Any help will be greatly appreciated.
Thanks
Slyesco:wall: (2 Replies)
I have to increase the date by one week in an input when script is executed in solaris. I was able to acheive this using ksh script that is working in Linux enivironment, when i execute the same script in Solaris i am getting below error:
/var/tmp\n\r-> ./script.ksh
date: illegal option -- d... (3 Replies)
Hi Sir/Madam
I have a file data.txt like below
file_name date_of_creation
x 2/10/2012
y 8/11/2010
z 11/3/2013
a 2/10/2013
b 3/10/2013
c ... (4 Replies)
Hi All,
I have a date variable say dt="2014-01-06 07:18:38"
Now i need to use this variable to search a log and get the entries which occured after that time. (1 Reply)
Hi,
My question is how to calculate the quarter end date according to the current date in shell script? (2 Replies)
Discussion started by: Divya_1234
2 Replies
LEARN ABOUT PHP
datetime.sub
DATETIME.SUB(3) 1 DATETIME.SUB(3)DateTime::sub - Subtracts an amount of days, months, years, hours, minutes and seconds from a DateTime object
Object oriented style
SYNOPSIS
public DateTime DateTime::sub (DateInterval $interval)
DESCRIPTION
Procedural style
DateTime date_sub (DateTime $object, DateInterval $interval)
Subtracts the specified DateInterval object from the specified DateTime object.
PARAMETERS
o $object
-Procedural style only: A DateTime object returned by date_create(3). The function modifies this object.
o $interval
- A DateInterval object
RETURN VALUES
Returns the DateTime object for method chaining or FALSE on failure.
EXAMPLES
Example #1
DateTime.sub(3) example
Object oriented style
<?php
$date = new DateTime('2000-01-20');
$date->sub(new DateInterval('P10D'));
echo $date->format('Y-m-d') . "
";
?>
Procedural style
<?php
$date = date_create('2000-01-20');
date_sub($date, date_interval_create_from_date_string('10 days'));
echo date_format($date, 'Y-m-d');
?>
The above examples will output:
2000-01-10
Example #2
Further DateTime.sub(3) examples
<?php
$date = new DateTime('2000-01-20');
$date->sub(new DateInterval('PT10H30S'));
echo $date->format('Y-m-d H:i:s') . "
";
$date = new DateTime('2000-01-20');
$date->sub(new DateInterval('P7Y5M4DT4H3M2S'));
echo $date->format('Y-m-d H:i:s') . "
";
?>
The above example will output:
2000-01-19 13:59:30
1992-08-15 19:56:58
Example #3
Beware when subtracting months
<?php
$date = new DateTime('2001-04-30');
$interval = new DateInterval('P1M');
$date->sub($interval);
echo $date->format('Y-m-d') . "
";
$date->sub($interval);
echo $date->format('Y-m-d') . "
";
?>
The above example will output:
2001-03-30
2001-03-02
NOTES DateTime.modify(3) is an alternative when using PHP 5.2.
SEE ALSO DateTime.add(3), DateTime.diff(3), DateTime.modify(3).
PHP Documentation Group DATETIME.SUB(3)