You could be simpler with xargs and a call to another mini-script. A starter might be something like:-
You can then run something like this:-
This will move 100 files at a time (specified by the xargs parameter after -n)
Is this possible? Let me know If I need specify further on what I am trying to do- I just want to spare you the boring details of my personal file management.
Thanks in advance-
Brian- (2 Replies)
Hi All,
I am coding for a requirement where I need to move files (filename.yymmdd) from one directory(A) to another(B) based on 2 date fields in a paramtere file. (Paramfile.txt)
For e.g: In Paramfile.txt,
BUS_DT =20120612
SUB_DT =20120602
In this case, i need to move all the files... (14 Replies)
Hi,
need to zip all files in a directory and move to another directory after the zip..
i am using this one but didnt help me...
zip -r my_proj_`date +%Y%m%d%H%MS`.zip /path/my_proj
mv in_proj_`date +%Y%m%d%H%M%S`.zip /path/source/
i am trying to zip all the files in my_proj... (0 Replies)
I have a directory e2e_ms_xfer/cent01
this contains the multiple files some of which will be named below with unique date time stamps
e2e_ms_edd_nom_CCYYMMDD_HHMM.csv
What I want to do is in a loop
1) Get the oldest file
2) Rename
3) Move it up one level from e2e_ms_xfer/cent01 to... (1 Reply)
I have a directory e2e_ms_xfer/cent01
this contains the multiple files some of which will be named below with unique date time stamps
e2e_ms_edd_nom_CCYYMMDD_HHMM.csv
What I want to do is in a loop
1) Get the oldest file
2) Rename
3) Move it up one level from e2e_ms_xfer/cent01 to... (1 Reply)
Hi all,
i have a folder, with tons of files containing as following,
on /my/folder/jobs/
some_name_2016-01-17-22-38-58_some name_0_0.zip.done
some_name_2016-01-17-22-40-30_some name_0_0.zip.done
some_name_2016-01-17-22-48-50_some name_0_0.zip.done
and these can be lots of similar files,... (6 Replies)
I want to move all the files in a given directory up one level.
For example:
Dir1
Subdir1
I want to move all the files in Subdir1 up to Dir1 (then I want to ultimately delete Subdir1)
Thanks,
Ted (10 Replies)
Hi All,
Daily i am doing the house keeping in one of my server and manually moving the files which were older than 90 days and moving to destination folder.
using the find command . Could you please assist me how to put the automation using the shell script .
... (11 Replies)
Hi All,
We have main directory called "head"
under this we have several sub directories and under these directories we have sub directories.
My requirement is I have to find the SQL files which are having the string "procedure" under "head" directory and sub directories as well.
And create... (14 Replies)
Discussion started by: ROCK_PLSQL
14 Replies
LEARN ABOUT DEBIAN
test::inline::content::legacy
Test::Inline::Content::Legacy(3pm) User Contributed Perl Documentation Test::Inline::Content::Legacy(3pm)NAME
Test::Inline::Content::Legacy - Test::Inline 2 Content Handler for legacy functions
SYNOPSIS
Custom script content generation using Test::Inline 2.000+ with a custom generator functions
my $header = "....";
my $function = sub {
my $Object = shift;
my $Script = shift;
return $header . $Script->merged_content;
};
my $Inline = Test::Inline->new(
...
file_content => $function,
);
Migrating this same code to Test::Inline 2.100+ ContentHandler objects
my $header = "....";
my $function = sub {
my $Object = shift;
my $Script = shift;
return $header . $Script->merged_content;
};
my $ContentHandler = Test::Inline::Content::Legacy->new( $function );
my $Inline = Test::Inline->new(
...
ContentHandler => $ContentHandler,
);
DESCRIPTION
This class exists to provide a migration path for anyone using the custom script generators in Test::Inline via the "file_content" param.
The synopsis above pretty much says all you need to know.
METHODS
new $CODE_ref
The "new" constructor for "Test::Inline::Content::Legacy" takes a single parameter of a "CODE" reference, as you would have previously
provided directly to "file_content".
Returns a new "Test::Inline::Content::Legacy" object, or "undef" if not passed a "CODE" reference.
coderef
The "coderef" accessor returns the "CODE" reference for the object
process $Inline $Script
The "process" method works with the legacy function by passing the Test::Inline and Test::Inline::Script arguments straight through to the
legacy function, and returning it's result as the return value.
SUPPORT
See the main SUPPORT section.
AUTHOR
Adam Kennedy <adamk@cpan.org>, <http://ali.as/>
COPYRIGHT
Copyright 2004 - 2010 Adam Kennedy.
This program is free software; you can redistribute it and/or modify it under the same terms as Perl itself.
The full text of the license can be found in the LICENSE file included with this module.
perl v5.12.4 2010-11-22 Test::Inline::Content::Legacy(3pm)