I have to display only those subscribers which are in "unconnected state" and the date is 90 days older than today's date.
Below command is used for this purpose:
Problem is that this expression is not getting evaluated : `( substr($11,2,8) -lt $dm )`
results into " 20170520 " which is correct.
Please help me to get this expression evaluated and compared correctly in the command.
Last edited by vbe; 08-18-2017 at 08:02 AM..
Reason: code tags please
I have a txt file like below:
testin.txt
AB
BC
CD
DE
I have the following awk script
BEGIN {flag1="N"}
/(AB)|(BC)|(CD)|(DE)/ {flag1="Y"}
END {print flag1}
>awk -f testin.awk testin.txt
Returns
Y (8 Replies)
Hello world,
I was wondering if there is a nicer way to write the following code (in AWK):
awk '
FNR==NR&&$1~/^m$/{tok1=1}
FNR==NR&&$1~/^m10$/{tok1=1}
' my_file
In fact, it looks for m2, m4, m6, m8 and m10 and then return a positive flag. The problem is how to define 10 thanks... (3 Replies)
Hi,
I am trying to do evaluate one numerical string after substitution.
++++++++++++++++==
What I have = "7.04+2.3Xlog(0.72e-6X1.0e6)X1.9596"
What I need = evaluate 7.04+2.3*log(0.72e-6*1.0e6)*1.9596 = 5.55941
what I am doing;
echo "7.04+2.3Xlog(0.72e-6X1.0e6)X1.9596" | awk... (2 Replies)
I have the following simplified code that I am planning on putting into a larger shell script. I have been butchering it to try and make work amongst google searches and reading awk documentation.
amixer sset Master toggle | awk '{ if ( /^ Front Left/ { print $7 } == // ) print "MUTED" }'I... (2 Replies)
Hi,
Could somebody help me in understanding the following awk expression:
awk -v n="POINT" '/%/{print $0 "\n" n ;next}1' < file name
Thanks,
Arun (6 Replies)
Hello,
I have big files which I wanna filter them based on first column.
first column should be one of these strings: chr2L || chr2R || chr3L || chr3R || chr4 || chrX
and something like chr2Lh or chrY or chrM3L is not accepted.
I used the following command:
awk '{ if ($1=="chr2L" ||... (5 Replies)
Hi All,
I have a doubt in awk print exp.
Where in some awk commands have seen a digit 1 appended at the end of the awk ,didnt remember the command .
like ..
cat file |awk '{print }1'
Could some one help in understanding these cases where we use them.
Regards,
Ganesh, (2 Replies)
I am trying to write a simple function to select values from a database and assign them to variables. It can have any number of arguments sent into it, and I want to assign the value retrieved to a different variable name for each argument sent in. So my code looks something like this:
... (6 Replies)
I want to create a conditional expression string and pass in an awk script. My script is as below...
comm="\$3 == "hello""
awk -F "^T" -v command="${comm}" ' {
if ( command ) { print "hye" }
}' testBut the statement "if ( command )" always evaluates to true which is not... (5 Replies)
Discussion started by: Saikat123
5 Replies
LEARN ABOUT PHP
px_date2string
PX_DATE2STRING(3)PX_DATE2STRING(3)px_date2string - Converts a date into a string.SYNOPSIS
string px_date2string (resource $pxdoc, int $value, string $format)
DESCRIPTION
Turns a date as it stored in the paradox file into human readable format. Paradox dates are the number of days since 1.1.0000. This func-
tion is just for convenience. It can be easily replaced by some math and the calendar functions as demonstrated in the example below.
PARAMETERS
o $pxdoc
- Resource identifier of the paradox database as returned by px_new(3).
o $value
- Value as stored in paradox database field of type PX_FIELD_DATE.
o $format
- String format similar to the format used by date(3). The placeholders support by this function is a subset of those supported by
date(3) (Y, y, m, n, d, j, L).
RETURN VALUES
Returns TRUE on success or FALSE on failure.
EXAMPLES
Example #1
Turn a paradox date into a human readable form
<?php
$px = px_new();
/* make up a date as it could be stored in */
/* a date field of a paradox db. */
/* 700000 days since 1.1.0000. */
$days = 700000;
/* Use the calendar functions to print a */
/* human readable format of the date */
echo jdtogregorian($days+1721425)."
";
/* px_date2string() outputs the same */
echo px_date2string($px, $days, "n/d/Y")."
";
px_delete($px);
?>
The above example will output:
7/15/1917
7/15/1917
SEE ALSO px_timestamp2string(3), jdtogregorian(3).
PHP Documentation Group PX_DATE2STRING(3)