07-24-2017
Wow. That's a good one. It worked. Thank you very much Scrutinizer
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1. UNIX for Dummies Questions & Answers
I can't seem to list all the files that begin with a lower case or upper case letter between a-m while being in that directory?
Please help I've tried everything from all the ls commands to even grep commands.
b (5 Replies)
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2. UNIX for Dummies Questions & Answers
Does any one know how to get a recursive directory listing in long format (showing owner, group, permission etc) without listing the files contained in the directories.
The following command also shows the files but I only want to see the directories.
ls -lrtR * (4 Replies)
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3. Programming
Hi,
From a Unix book, i'd found that the way to list files in a directory.
But those file info are all not shown, wat is shown is only the file name.
Can anyone pls teach me how to show the file details?
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my code:
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struct... (3 Replies)
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4. Solaris
Hi experts,
I have several hundred files for everyday each month (below example is September)-
PP023149200709010546.......PP028023200709012300
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..
..
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5. Shell Programming and Scripting
if i am having files as below in a directory----
-rwxrwxrwx 1 dsadm dstage 43 Nov 21 2005 CheckfreeFtpSeq.err
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6. Shell Programming and Scripting
Hi,
I am trying to get a file name only. Could anyone help me on the same.
Meaning I have a file say list.out which holds below output
./xyz/abc.txt
./xyz/hij.txt
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abc.txt
hij.txt
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Hello.
I want to make an unix script which create a file with the name and the date of creation of the different files that there are in a directory.
Can do you please help me?
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8. UNIX for Dummies Questions & Answers
Hi,
I want to list out the files for a particular date recursively along with timestamp and directory name .
I tried using command
ls -lRt this list out all the files along with directory structure
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9. UNIX for Dummies Questions & Answers
Hi All,
Could you please help to resolve my following issues:
Problem Description:
Suppose my user name is "MI90".
i.e. $USER = MI90
when i run below command, i get all the processes running on the system containing name MQ.
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10. Shell Programming and Scripting
Legends,
I have following contents in the file and i want to list out non-zero values only out of it.
OPge1 03
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OPge11 3
OPCge12 0
OPCge13 0
OPge14 25
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for line in `cat /tmp/raw`
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LEARN ABOUT CENTOS
crontabs
CRONTABS(4) Crontabs users' Manual CRONTABS(4)
NAME
crontabs - configuration and scripts for running periodical jobs
SYNOPSIS
run-parts [--list|--test]<directory>
DESCRIPTION
Crontabs is a historical name for the run-parts script and the system crontab. The run-parts script runs all executables in the specified
directory. Run-parts runs all executables in the specified directory. The execution of files can be allowed or denied by creating file
jobs.allow or jobs.deny which worked similar as other allow/deny config files. The file must be created in the specified directory.
--list print names of all files (not limited to executables), but don't run them. This option can't be used with test option.
--test print names of files, which would be run.
Randomization of jobs can be configured in the /etc/sysconfig/run-parts file. To enable randomization of jobs, set the RANDOMIZE
parameter to 1 and set the RANDOM parameter to an integer which determines a random seed. Additionally, you may configure the RAN-
DOMTIME parameter (again, by specifying an integer) to provide an additional level of randomization. Jobs are not randomized when
the RANDOM and RANDOMTIME parameters are set to 0. Values in these two parameters must be set to 1 or larger to provide a good
enough randomization.
Randomization of cron jobs can be useful for shared networks, where multiple cron jobs executed at once can cause spikes in traffic,
especially during daily jobs. With randomized jobs, the workload is evenly distributed throughout the day.
EXAMPLE OF CONFIGURATION FILE
RANDOMIZE=1
RANDOM=4
RANDOMTIME=8
Historically the crontab file contained configuration which called run-parts on files in cron.{daily,weekly,monthly} directories. These
jobs are now run indirectly through anacron to prevent conflicts between cron and anacron. That means the anacron package has to be
installed if the jobs in these directories should be running. Refer to the anacron(8) how to limit the time of day of the job execution.
EXAMPLE
/etc/cron.daily/jobs.deny could contain for example 0logwatch which forbid execution of this script.
SEE ALSO
anacron(8), crontab(5)
Marcela Malaova 2012-08-29 CRONTABS(4)