My opinion is that coding date arithmetic and not using existing tools is foolish and error prone. I cannot tell what system you are on, most systems have perl.
If you are on Linux I would HIGHLY recommend that you use the date command which is very reliable and actually supports options like yesterday and tomorrow. Skip using the perl above.
Can anyone help please. I am writing a kourne shell script and I am unsure how to do the following:
I have extracted a time string from a logfile, and I have another time string I want to compare it to to see if it's later than the time I'm comparing with.
i.e. expectedSLA="23:00:00", ... (2 Replies)
i am used to making scripts for hp-ux. but lately i tried to make some for solaris. the problem is that when i tried to execute it it gave me an error the "let: not found". why is that? how can i perform an arithmetic function in the solaris shell script?
thanks :) (2 Replies)
Helloo..
I am trying one very simple thing I could not find anything on google..
I have 2 integer variable..and I need to do division...in ksh
where $catch and $num are integer variable..
I tryed with this:
printf "%0.2f" $final=$catch/$num
but it does not work..
any help is... (12 Replies)
Hi all,
I would appreciate if anyone knows how to perform adding to date.
As for normal date, i can easily plus with any number.
But when it comes to month end say for example 28 Jun, i need to perform a plus with number 3, it will not return 1 Jul.
Thanks in advance for your help. (4 Replies)
Hi Friends,
please advise on shell script to add two time stamps
for example :
a=12:32
b=12:00
c=a+b=00:32
please help me to find shell script to add to two time stamps, as i need to convert time from EST to GMT or SST to prepare status of jobs in unix and to specify estimated time to... (3 Replies)
Hello all,
I'd like to know how to perform arithmetic on multiple files. I have got many tab-delimited files. Each file contains about 2000 rows and 2000 columns.
What I want to do is to to sum the values in each row & column in every file.
The following explains what I want to do;
... (9 Replies)
Hi,
I need to process a file which contains below data. Usually the files contains both Start and Finish time. but for Few records, it contains only Start. For those records I need to add the finish line by adding 5 minutes to Start time.
Started BBIDX Tue Jun 1 15:15:11 EDT 2010 292308... (1 Reply)
Discussion started by: siba.s.nayak
1 Replies
8. Post Here to Contact Site Administrators and Moderators
page
unix com/answers-frequently-asked-questions/13785-yesterdays-date-date-arithmetic.html
Date Arithmetic with the Shell
has link of
www samag com/documents/s=8284/sam0307b/0307b.htm
which is no longer.
Is this the correct place to post this?:confused:
and I got message... (1 Reply)
I have a file (main.lst) containing a list of dates in DDMMYYYY format. The dates will mostly be the same but it is possible to have multiple dates and these need not be in chronological order. I have another file containing another list of dates (holidays.lst).
The task is to get the latest... (5 Replies)
I need to divide the number of white spaces by total number of characters in a file using bash. I am able to get the number of white spaces correctly using:
tr -cd < afile | wc -c
I am also able to get the total number of characters using:
wc -c afile
How do I divide the first... (2 Replies)
Discussion started by: ngabrani
2 Replies
LEARN ABOUT CENTOS
time::seconds
Time::Seconds(3pm) Perl Programmers Reference Guide Time::Seconds(3pm)NAME
Time::Seconds - a simple API to convert seconds to other date values
SYNOPSIS
use Time::Piece;
use Time::Seconds;
my $t = localtime;
$t += ONE_DAY;
my $t2 = localtime;
my $s = $t - $t2;
print "Difference is: ", $s->days, "
";
DESCRIPTION
This module is part of the Time::Piece distribution. It allows the user to find out the number of minutes, hours, days, weeks or years in a
given number of seconds. It is returned by Time::Piece when you delta two Time::Piece objects.
Time::Seconds also exports the following constants:
ONE_DAY
ONE_WEEK
ONE_HOUR
ONE_MINUTE
ONE_MONTH
ONE_YEAR
ONE_FINANCIAL_MONTH
LEAP_YEAR
NON_LEAP_YEAR
Since perl does not (yet?) support constant objects, these constants are in seconds only, so you cannot, for example, do this: "print
ONE_WEEK->minutes;"
METHODS
The following methods are available:
my $val = Time::Seconds->new(SECONDS)
$val->seconds;
$val->minutes;
$val->hours;
$val->days;
$val->weeks;
$val->months;
$val->financial_months; # 30 days
$val->years;
$val->pretty; # gives English representation of the delta
The usual arithmetic (+,-,+=,-=) is also available on the objects.
The methods make the assumption that there are 24 hours in a day, 7 days in a week, 365.24225 days in a year and 12 months in a year.
(from The Calendar FAQ at http://www.tondering.dk/claus/calendar.html)
AUTHOR
Matt Sergeant, matt@sergeant.org
Tobias Brox, tobiasb@tobiasb.funcom.com
BalieXXzs SzabieXX (dLux), dlux@kapu.hu
LICENSE
Please see Time::Piece for the license.
Bugs
Currently the methods aren't as efficient as they could be, for reasons of clarity. This is probably a bad idea.
perl v5.16.3 2013-03-04 Time::Seconds(3pm)