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Top Forums Shell Programming and Scripting Need help with date arithmetic please Post 303000250 by ektubbe on Friday 7th of July 2017 10:45:08 AM
Old 07-07-2017
Need help with date arithmetic please

Hello fellow forum members,

I wrote below piece of code to calculate the date after a given date -
Code:
date=$DATE_FINAL
declare -a  max_month=(0 31 28 31 30 31 30 31 31 30 31 30 31)
eval $(echo $date|sed 's!\(....\)\(..\)\(..\)!year=\1;month=\2;day=\3!')
(( year4=year%4 ))
(( year100=year%100 ))
(( year400=year%400 ))
if [ \( $year4 -eq 0 -a \
        $year100 -ne 0 \) -o \
     $year400 -eq 0 ]
then
declare -a  max_month=(0 31 28 31 30 31 30 31 31 30 31 30 31)
fi
day=$((day+1))
if [ $day -gt ${max_month[$month]} ] >| /wload/baot/home/baoted9/logs_bde27_conversion_1/ataa_display.logs 2>&1
then
  day=1
  month=$((month+1))
  if [ $month -gt 12 ]
  then
    year=$((year+1))
    month=1
  fi
fi
if [ $month -eq "08" ] ||  [ $month -eq "09" ]
then
future_date_final=$(echo $year"$month"$day)
else
future_date_final=$(printf "%4.4d%2.2d%2.2d" $year $month $day)
fi
echo "this is your final business date $future_date_final"

It calculates the date correctly however throws an error at the end of the code as below -
Code:
line 79: 08: value too great for base (error token is "08")

It just looks too ugly, not sure how to remove it as otherwise code is working fine, tried redirecting it to a log file still appearing.
Also, I am facing issue with below code for a plain cd command with code highlighted in red -
Code:
echo "pset  date $Param_date_1"
cd /wload/baot/home/baotasa0/sandboxes_finance/ext_ukba_bde/pset >| /wload/baot/home/baoted9/logs_bde27_conversion_1/at_display.logs 2>&1
sh UKBA_publish.sh UKBA $Param_date_1 3 >| /wload/baot/home/baoted9/logs_bde27_conversion_1/ate_display.logs 2>&1

Error is -
Code:
./auto2.sh: line 190: syntax error: unexpected end of file

Any leads will be greatly appreciated.

Last edited by ektubbe; 07-07-2017 at 11:48 AM.. Reason: Wanted to add tags
 

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CAL_FROM_JD(3)								 1							    CAL_FROM_JD(3)

cal_from_jd - Converts from Julian Day Count to a supported calendar

SYNOPSIS
array cal_from_jd (int $jd, int $calendar) DESCRIPTION
cal_from_jd(3) converts the Julian day given in $jd into a date of the specified $calendar. Supported $calendar values are CAL_GREGORIAN, CAL_JULIAN, CAL_JEWISH and CAL_FRENCH. PARAMETERS
o $jd - Julian day as integer o $calendar - Calendar to convert to RETURN VALUES
Returns an array containing calendar information like month, day, year, day of week, abbreviated and full names of weekday and month and the date in string form "month/day/year". EXAMPLES
Example #1 cal_from_jd(3) example <?php $today = unixtojd(mktime(0, 0, 0, 8, 16, 2003)); print_r(cal_from_jd($today, CAL_GREGORIAN)); ?> The above example will output: Array ( [date] => 8/16/2003 [month] => 8 [day] => 16 [year] => 2003 [dow] => 6 [abbrevdayname] => Sat [dayname] => Saturday [abbrevmonth] => Aug [monthname] => August ) SEE ALSO
cal_to_jd(3), jdtofrench(3), jdtogregorian(3), jdtojewish(3), jdtojulian(3), jdtounix(3). PHP Documentation Group CAL_FROM_JD(3)
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