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Full Discussion: Gunzip and edit many files
Top Forums Shell Programming and Scripting Gunzip and edit many files Post 303000246 by bakunin on Friday 7th of July 2017 08:59:02 AM
Old 07-07-2017
Quote:
Originally Posted by timj123
Thanks for the reply.
Sorry if I wasn't very clear.

I'm trying to gunzip many files and run them through a sed script for further processing before they get written to a file.
OK, we have understood that. Still, What RudiC has said holds:

Code:
gunzip -c "${i}" | $HOME/insert.sh > tmp/"${FILE}"

Here the script $HOME/insert.sh is called, but without any parameter, but here:

Code:
startTime="$(grep "<Setup" $1)</Setup>"
dn=$(grep -m1 "DN" $1)

It seems that one parameter to this script is required, no? So the line in script one should look like

Code:
gunzip -c "${i}" | $HOME/insert.sh "some-param-here" > tmp/"${FILE}"

and whatever yo put into "some-param-here" will end up where you use "$1" in the insert.sh-script.


Another thing is that obviously insert.sh expects the parameter to be a file(name), because otherwise this line:

Code:
sed  -e "/<Target/a\ $dn" -e "/<Target/a \ \ \ \ \ \ $startTime" $1 > $1.chg

wouldn't make any sense at all. But you do not pass a filename to insert.sh, instead you flood its stdin with input. insert.sh has no method to deal with input from stdin, though. It is as if you are writing someone a letter who is only expecting telephone calls. Because he watches the phone the whole day but doesn't check his mailbox you can write as many letters as you want, he won't react.

I hope this helps.

bakunin

Last edited by vbe; 07-07-2017 at 10:47 AM.. Reason: missing square bracket...
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