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Top Forums Shell Programming and Scripting Need to minus one day from a date given Post 303000132 by Chubler_XL on Tuesday 4th of July 2017 07:05:46 PM
Old 07-04-2017
You could use perl

save this as dayadd.pl:
Code:
#! /usr/bin/env perl
use Time::Local;
use POSIX qw(strftime);

 my ($yy, $mm, $dd) = unpack "A4A2A2", $ARGV[0];
 eval { print strftime("%Y%m%d\n", localtime(timelocal(0,0,0,$dd,$mm - 1,$yy) + $ARGV[1]*24*60*60)) } ;
 exit 1 if $@ ;
 exit 0;

Then you can use it like this:
Code:
$ ./dayadd.pl 20141220 -1 || echo "Invalid date!"
20141219

$ ./dayadd.pl 20132202 -1 || echo "Invalid date"
Invalid date


Last edited by Chubler_XL; 07-04-2017 at 08:22 PM..
This User Gave Thanks to Chubler_XL For This Post:
 

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DATE_PARSE_FROM_FORMAT(3)						 1						 DATE_PARSE_FROM_FORMAT(3)

date_parse_from_format - Get info about given date formatted according to the specified format

SYNOPSIS
array date_parse_from_format (string $format, string $date) DESCRIPTION
Returns associative array with detailed info about given date. PARAMETERS
o $format - Format accepted by DateTime.createFromFormat(3). o $date - String representing the date. RETURN VALUES
Returns associative array with detailed info about given date. EXAMPLES
Example #1 date_parse_from_format(3) example <?php $date = "6.1.2009 13:00+01:00"; print_r(date_parse_from_format("j.n.Y H:iP", $date)); ?> The above example will output: Array ( [year] => 2009 [month] => 1 [day] => 6 [hour] => 13 [minute] => 0 [second] => 0 [fraction] => [warning_count] => 0 [warnings] => Array ( ) [error_count] => 0 [errors] => Array ( ) [is_localtime] => 1 [zone_type] => 1 [zone] => -60 [is_dst] => ) SEE ALSO
DateTime.createFromFormat(3), checkdate(3). PHP Documentation Group DATE_PARSE_FROM_FORMAT(3)
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