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Top Forums UNIX for Advanced & Expert Users Command to check memory used or consumed by OS kernel Post 303000085 by bakunin on Tuesday 4th of July 2017 05:16:22 AM
Old 07-04-2017
Quote:
Originally Posted by sam@sam
I am trying to check how much memory is consumed by OS Kernel using below command, Is this the correct command that I'm using

Code:
grep Slab /proc/meminfo

According to this document this is not (quite) the correct command. To quote the linked explanation:

Quote:
Slab - The total amount of memory, in kilobytes, used by the kernel to cache data structures for its own use.
Note that "kernel" isn't a monolithic process. In fact the "kernel" consists of several processes, depending on how the system is configured, what it is doing, how much memory it has installed and perhaps a few other things. So it is difficult to point to one certain place and declare it to be the answer. The value you found is arguably part of the answer but if it is depends on what exactly the question is.

Can you tell us what exactly you want, so that maybe we can find some better solution?

I hope this helps.

bakunin
 

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SHELL-QUOTE(1)						User Contributed Perl Documentation					    SHELL-QUOTE(1)

NAME
shell-quote - quote arguments for safe use, unmodified in a shell command SYNOPSIS
shell-quote [switch]... arg... DESCRIPTION
shell-quote lets you pass arbitrary strings through the shell so that they won't be changed by the shell. This lets you process commands or files with embedded white space or shell globbing characters safely. Here are a few examples. EXAMPLES
ssh preserving args When running a remote command with ssh, ssh doesn't preserve the separate arguments it receives. It just joins them with spaces and passes them to "$SHELL -c". This doesn't work as intended: ssh host touch 'hi there' # fails It creates 2 files, hi and there. Instead, do this: cmd=`shell-quote touch 'hi there'` ssh host "$cmd" This gives you just 1 file, hi there. process find output It's not ordinarily possible to process an arbitrary list of files output by find with a shell script. Anything you put in $IFS to split up the output could legitimately be in a file's name. Here's how you can do it using shell-quote: eval set -- `find -type f -print0 | xargs -0 shell-quote --` debug shell scripts shell-quote is better than echo for debugging shell scripts. debug() { [ -z "$debug" ] || shell-quote "debug:" "$@" } With echo you can't tell the difference between "debug 'foo bar'" and "debug foo bar", but with shell-quote you can. save a command for later shell-quote can be used to build up a shell command to run later. Say you want the user to be able to give you switches for a command you're going to run. If you don't want the switches to be re-evaluated by the shell (which is usually a good idea, else there are things the user can't pass through), you can do something like this: user_switches= while [ $# != 0 ] do case x$1 in x--pass-through) [ $# -gt 1 ] || die "need an argument for $1" user_switches="$user_switches "`shell-quote -- "$2"` shift;; # process other switches esac shift done # later eval "shell-quote some-command $user_switches my args" OPTIONS
--debug Turn debugging on. --help Show the usage message and die. --version Show the version number and exit. AVAILABILITY
The code is licensed under the GNU GPL. Check http://www.argon.org/~roderick/ or CPAN for updated versions. AUTHOR
Roderick Schertler <roderick@argon.org> perl v5.16.3 2010-06-11 SHELL-QUOTE(1)
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