Thank you for the solution, but I do not deal with system date, it is an arbitary date given by the system and I need to minus a day from it.
Quote:
Originally Posted by bakunin
You don't need date -d for this type of things - use the TZ-variable (Time Zone) instead.
You see, time ist stored in "UTC" (universal time coordinated) in UNIX systems. the local time is just an offset from this, and this offset is set by the TZ variable, which you can change for a single command, for instance:
You see, adding/subtracting 24 to the TZ variable changes the output by 24 hours - which is a day. The same way you can get any arbitrary date, even in the future:
Hi All,
I need to find the previous month last day minus one day, using shell script. Can you guys help me to do this.
My Requirment is as below:
Input for me will be 2000909(YYYYMM)
I need the previous months last day minus 1 day timestamp. That is i need 2000908 months last day minus ... (3 Replies)
Hi
I have a table with name, date in format DD.MM.YYYY.
I need to something like this (I try to explain in pseudo code)
if SYSDATE (current date) minus 6 months > $expiry date
print OK
else print NOK with $name and $expiry date
I know this is possible with Oracle. How to do this... (0 Replies)
Hi guys,
I had a scenario...
1. I had to get the previous days date in yyyymmdd format
2. i had to create a file with Date inthe format yyyymmdd.txt format
both are different
thanks guys in advance.. (4 Replies)
I need to get the next day's date of the user entered date
for example:
Enter date (yyyy/mm/yy):
2013/10/08I need to get the next day's date of the user entered date
Desired Output:
2013/10/09Though there are ways to achieve this is Linux or Unix environment (date command) ,I need to... (1 Reply)
Hi there,
is it possible to get the actual date minux six months with just a simple command?
It's easy with Linux but on HP Unix (for me) impossible ;)
Best wishes (3 Replies)
I am running a script in ksh to get the 2 months back date from system date.The below code is giving correct date output from putty command prompt.But while running the script is .ksh file it is giving the error below.Please suggest.
; d=a; y=a
m-=num
while(m < 1) {m+=12; y--}... (1 Reply)
Hi the below code is failing i am trying to generate do the following:
2014-10-22 11:26:00 (Substract 24 hrs)
should produce
2014-10-21 11:26:00
I need the same formatting below because that gets inputted into code for an... (4 Replies)
I Have text like
XXX_20190908.csv.gz need to replace Only date in this format with current date every day
Thanks! (1 Reply)
Discussion started by: yamasani1991
1 Replies
LEARN ABOUT ULTRIX
date
date(1) General Commands Manual date(1)Name
date - print date and time
Syntax
date [-c | -u] [ +format ] [[yy[mm[dd]]]hhmm[.ss][-[-]tttt][z]]
Description
If no argument is given, or if the argument begins with +, the current date and time are printed. Otherwise, the current date is set. The
first mm is the month number; dd is the day number in the month; hh is the hour number (24 hour clock); the second mm is the minute number;
.ss the second; -[-]tttt is the minutes west of Greenwich; a positive number means your time zone is west of Greenwich (for example, North
and South America) and a negative number means it is east of Greenwich (for example Europe); z is a one letter code indicating the dst cor-
rection mode (n=none, u=usa, a=australian, w=western europe, m=middle europe, e=eastern europe); yy is the last 2 digits of the year number
and is optional. The following example sets the date to Oct 8, 12:45 AM:
date 10080045
The current year is the default if no year is mentioned. The system operates in GMT. The takes care of the conversion to and from local
standard and daylight time.
If the argument begins with +, the output of is under the control of the user. The format for the output is similar to that of the first
argument to All output fields are of fixed size (zero padded if necessary). Each field descriptor is preceded by % and is replaced in the
output by its corresponding value. A single % is encoded by %%. All other characters are copied to the output without change. The string
is always terminated with a new-line character.
Options-c Perform operations using Coordinated Universal Time (UCT) instead of the default local time. The UCT does not use leap seconds so
UCT is the same as GMT.
-u Perform operations using Greenwich Mean Time (GMT) instead of the default local time.
+ format
The following is a list of field Descriptors that can be used in the format (Note: date exits after processing format information) :
%a Locale's abbreviated weekday name
%A Locale's full weekday name
%b Locale's abbreviated month name
%B Locale's full month name
%c Locale's date and time representation
%d Day of month as a decimal number (01-31)
%D Date (%m/%d/%y)
%h Locale's abbreviated month name
%H Hour as a decimal number (00-23)
%I Hour as a decimal number (01-12)
%j Day of year (001-366)
%m Number of month (01-12)
%M Minute number (00-59)
%n Newline character
%p Locale's equivalent to AM or PM
%r Time in AM/PM notation
%S Second number (00-59)
%t Tab character
%T Time (%H/%M/%S)
%U Week number (00-53), Sunday as first day of week
%w Weekday number (0[Sunday]-6)
%W Week number (00-53), Monday as first day of week
%x Locale's date representation
%X Locale's time representation
%y Year without century (00-99)
%Y Year with century
%Z Timezone name, no characters if no timezone
%% %
Examples
The following command line
date +%m/%d/%y
generates the following output
04/02/89
The following command line
date +"DATE: %m/%d/%y%nTIME: %H:%M:%S"
generates the following output
DATE: 04/02/89
TIME: 14:45:05
The quotes (") are necessary because the format contains blank characters. Use single quotes (') to prevent interpretation by the shell.
Diagnostics
Failed to set date: Not owner
You are not the super-user and you tryed to change the date. Do not change the date while the system is running in multiuser mode.
Restrictions
An attempt to set a date to before 1/1/1970 will result in the date being set to 1/1/1970.
Files
/dev/kmem
date(1)