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Top Forums Programming Appending a column in xlsx file using Python Post 302999644 by nans on Saturday 24th of June 2017 07:15:33 AM
Old 06-24-2017
It still doesn;t work for me. the code runs but doesn't give any output at all or print 'dict_pos'. I have attached the code I am using now.


Code:
#!/usr/bin/python

import sys
sys.path.append('/usr/local/lib/python2.7/site-packages')

import os
from openpyxl import load_workbook
from datetime import datetime
import csv

# Variables
sheet_directory = r'/home/test'
text_directory = r'/home/test'

# Subroutines
def get_text_data(txt_filename):
    dict_pos = {}
    first_line = True
    with open('scores.txt') as txt_filename:
        tab_reader = csv.reader(txt_filename, delimiter='\t')
        for line in tab_reader:
            if first_line:
                first_line = False
                continue
            line = line.rstrip('\n')
            x = line.split('\t')
            dict_pos[x[0]] = x[3]
        print dict_pos          
        return dict_pos


def process_xl_sheets():
    for sheet_root, sheet_dirs, sheet_files in os.walk(sheet_directory):
        for sheet_file in sheet_files:
            if sheet_file.endswith('.xlsx'):
                dpos = get_text_data(sheet_file.replace('.xlsx', '.txt'))
                sheet_xl_file = os.path.join(sheet_root, sheet_file)
                wb = load_workbook(sheet_xl_file, data_only=True)
                ws = wb.get_sheet_by_name('raw_data')
                pos_col_no = 'F'
                score_col_no = 'V'
                row_no = 4
                cell = ws[pos_col_no + str(row_no)]
                while cell.value:
                    if str(cell.value) in dpos:
                        ws[score_col_no + str(row_no)] = dpos[str(cell.value)]
                    else:
                        ws[score_col_no + str(row_no)] = 'Unknown_' + datetime.now().strftime("%B") + datetime.now().strftime("%Y")
                        row_no += 1
                        cell = ws[pos_col_no + str(row_no)]
                wb.save(sheet_xl_file)

# Main section
process_xl_sheets()

 

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SHTOOL-PATH.TMP(1)					      GNU Portable Shell Tool						SHTOOL-PATH.TMP(1)

NAME
shtool-path - GNU shtool command dealing with shell path variables SYNOPSIS
shtool path [-s|--suppress] [-r|--reverse] [-d|--dirname] [-b|--basename] [-m|--magic] [-p|--path path] str [str ...] DESCRIPTION
This command deals with shell $PATH variables. It can find a program through one or more filenames given by one or more str arguments. It prints the absolute filesystem path to the program displayed on "stdout" plus an exit code of 0 if it was really found. OPTIONS
The following command line options are available. -s, --suppress Supress output. Useful to only test whether a program exists with the help of the return code. -r, --reverse Transform a forward path to a subdirectory into a reverse path. -d, --dirname Output the directory name of str. -b, --basename Output the base name of str. -m, --magic Enable advanced magic search for ""perl"" and ""cpp"". -p, --path path Search in path. Default is to search in $PATH. EXAMPLE
# shell script awk=`shtool path -p "${PATH}:." gawk nawk awk` perl=`shtool path -m perl` cpp=`shtool path -m cpp` revpath=`shtool path -r path/to/subdir` HISTORY
The GNU shtool path command was originally written by Ralf S. Engelschall <rse@engelschall.com> in 1998 for Apache. It was later taken over into GNU shtool. SEE ALSO
shtool(1), which(1). 18-Jul-2008 shtool 2.0.8 SHTOOL-PATH.TMP(1)
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