06-23-2017
Why is your output mm/dd/yyyy when your example shows output as dd/mm/yyyy?
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date: extra operand `+%s'
Try `date --help' for more information.
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LEARN ABOUT PHP
datefmt_get_pattern
DATEFMT_GET_PATTERN(3) 1 DATEFMT_GET_PATTERN(3)
IntlDateFormatter::getPattern - Get the pattern used for the IntlDateFormatter
Object oriented style
SYNOPSIS
public string IntlDateFormatter::getPattern (void )
DESCRIPTION
Procedural style
string datefmt_get_pattern (IntlDateFormatter $fmt)
Get pattern used by the formatter.
PARAMETERS
o $fmt
- The formatter resource.
RETURN VALUES
The pattern string being used to format/parse.
EXAMPLES
Example #1
datefmt_get_pattern(3) example
<?php
$fmt = datefmt_create(
'en_US',
IntlDateFormatter::FULL,
IntlDateFormatter::FULL,
'America/Los_Angeles',
IntlDateFormatter::GREGORIAN,
'MM/dd/yyyy'
);
echo 'pattern of the formatter is : ' . datefmt_get_pattern($fmt);
echo 'First Formatted output with pattern is ' . datefmt_format($fmt, 0);
datefmt_set_pattern($fmt,'yyyymmdd hh:mm:ss z');
echo 'Now pattern of the formatter is : ' . datefmt_get_pattern($fmt);
echo 'Second Formatted output with pattern is ' . datefmt_format($fmt, 0);
?>
Example #2
OO example
<?php
$fmt = new IntlDateFormatter(
'en_US',
IntlDateFormatter::FULL,
IntlDateFormatter::FULL,
'America/Los_Angeles',
IntlDateFormatter::GREGORIAN,
'MM/dd/yyyy'
);
echo 'pattern of the formatter is : ' . $fmt->getPattern();
echo 'First Formatted output is ' . $fmt->format(0);
$fmt->setPattern('yyyymmdd hh:mm:ss z');
echo 'Now pattern of the formatter is : ' . $fmt->getPattern();
echo 'Second Formatted output is ' . $fmt->format(0);
?>
The above example will output:
pattern of the formatter is : MM/dd/yyyy
First Formatted output is 12/31/1969
Now pattern of the formatter is : yyyymmdd hh:mm:ss z
Second Formatted output is 19690031 04:00:00 PST
SEE ALSO
datefmt_set_pattern(3), datefmt_create(3).
PHP Documentation Group DATEFMT_GET_PATTERN(3)