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Top Forums UNIX for Beginners Questions & Answers Parsing a column of text file - best practices Post 302997888 by SIMMS7400 on Monday 22nd of May 2017 05:23:57 PM
Old 05-22-2017
Hi Don -

Sorry for the confusion.

The shell I am using is bash.

I've updated how i calculated calendar quarter with your code:

Code:
_QUARTER=$(((month+2)/3))

As far as examples, here they are.

For Q1 of 2017:
FirstQtrWeek:12/31/16
LastQtrWeek: 03/25/17

For Q2 of 2017:
FirstQtrWeek:04/01/17
LastQtrWeek: 06/24/17

For Q3 of 2017:
FirstQtrWeek:07/01/17
LastQtrWeek: 09/23/17

For Q4 of 2017:
FirstQtrWeek:09/30/17
LastQtrWeek: 12/23/17

I'm sorry for the run around!

---------- Post updated at 05:23 PM ---------- Previous update was at 04:11 AM ----------

I've found out how to get the last Saturday of the quarter, however still having trouble getting the first Saturday:

Code:
GetFirstLastWeek () { 

DAY_OF_WEEK=6 # 1=Monday, ..., 7=Sunday
THE_YEAR=${_YEAR}
THE_MONTH="$1"

RESULT_DAY=0

YEAR_MONTH_STR=${THE_YEAR}"-"${THE_MONTH}  # Example value: "2017-06"

for DAYNO in 22 23 24 25 26 27 28 29 30 31
do
  DATE_TO_CHECK=${YEAR_MONTH_STR}"-"${DAYNO}
  DATE_RESULT=$(date --date=$DATE_TO_CHECK '+%u')
  if [ $? -eq 0 ]
  then
    if [ $DATE_RESULT -eq $DAY_OF_WEEK ]
    then
      RESULT_DAY=$DAYNO
    fi
  fi
done

RESULT_DATE_COMPLETE=${YEAR_MONTH_STR}"-"${RESULT_DAY}

echo $(date --date=$RESULT_DATE_COMPLETE +FirstQtrWeek,%m/%d/%Y -d "4 weeks ago")
echo $(date --date=$RESULT_DATE_COMPLETE +LastQtrWeek,%m/%d/%Y)

} > ${_SUBVARPATH}${_YEAR}_${_MONTH}${_DAY}/Subvar_List.txt

4 weeks ago from the LastQtrWeek doesn't work, obviously.
 

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DATETIME.ADD(3) 							 1							   DATETIME.ADD(3)

DateTime::add - Adds an amount of days, months, years, hours, minutes and seconds to a DateTime object

       Object oriented style

SYNOPSIS
public DateTime DateTime::add (DateInterval $interval) DESCRIPTION
Procedural style DateTime date_add (DateTime $object, DateInterval $interval) Adds the specified DateInterval object to the specified DateTime object. PARAMETERS
o $object -Procedural style only: A DateTime object returned by date_create(3). The function modifies this object. o $interval - A DateInterval object RETURN VALUES
Returns the DateTime object for method chaining or FALSE on failure. EXAMPLES
Example #1 DateTime.add(3) example Object oriented style <?php $date = new DateTime('2000-01-01'); $date->add(new DateInterval('P10D')); echo $date->format('Y-m-d') . " "; ?> Procedural style <?php $date = date_create('2000-01-01'); date_add($date, date_interval_create_from_date_string('10 days')); echo date_format($date, 'Y-m-d'); ?> The above examples will output: 2000-01-11 Example #2 Further DateTime.add(3) examples <?php $date = new DateTime('2000-01-01'); $date->add(new DateInterval('PT10H30S')); echo $date->format('Y-m-d H:i:s') . " "; $date = new DateTime('2000-01-01'); $date->add(new DateInterval('P7Y5M4DT4H3M2S')); echo $date->format('Y-m-d H:i:s') . " "; ?> The above example will output: 2000-01-01 10:00:30 2007-06-05 04:03:02 Example #3 Beware when adding months <?php $date = new DateTime('2000-12-31'); $interval = new DateInterval('P1M'); $date->add($interval); echo $date->format('Y-m-d') . " "; $date->add($interval); echo $date->format('Y-m-d') . " "; ?> The above example will output: 2001-01-31 2001-03-03 NOTES
DateTime.modify(3) is an alternative when using PHP 5.2. SEE ALSO
DateTime.sub(3), DateTime.diff(3), DateTime.modify(3). PHP Documentation Group DATETIME.ADD(3)
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