The purpose of those comands are to find the newest file in a directory acvrdind to system date, and it has to be recursively found in each directory.
The problem is that i want to list in a long format every found file, but the commands i use produce unexpected results ,so the output lists in a... (5 Replies)
I would like ot create shell script/ bash to create diffrent files based on a file and parameters list.
Here is the detail example: I have a textfile and four static parameter files (having ‘?'). mainfile.txt has below records (this count may be more than 50)
A200001
A200101
B200001... (9 Replies)
Evening all. I'm having a terrible time with a script I've been working on for a few days now...
Say I have a text file named top10song.tm2, with the following in it:
kernkraft 400
Imagine
i kissed a girl
Thriller
animals
hallelujah
paint it black
psychosocial
Oi to the world... (14 Replies)
I'd like to grep files for key words using korn shell, and compile the actual contents (not just file name) of those files that contain a combination of those grepped key words into one repository file for reference. However, I'm stuck at the combining part. Here's what I have thus far:
egrep... (5 Replies)
counter=0;
while read line;
do ] && let counter=counter+1; done < input_file.txt
echo $counter
The above code is reading a file line by line and checking whether the filenames mentioned in the file exist or not .
At present the o/p is value of counter
I want to echo out the name of... (5 Replies)
I have an issue with a korn shell script that I am writing. The script parses through a configuration file which lists a heap of path/directories for some files which need to be FTP'd. Now the script needs to check whether there are any files which have not been processed and are X minutes old.
... (2 Replies)
Hi All,
I need to list the files based modification time of the files from a directory, I cannot use "ls -t" as there are lot of files, which "ls" command cannot handle. New files will land there daily. So iam looking for an alternative through "find"command.
All suggestions are welcomed.
... (6 Replies)
Hi,
I'm writing a post-upgrade script and I want to find which files don't have read and execute to everyone.
I can run a find . ! -perm, but then I have to use a list of the possible permissions (777,775, 755 etc). Is there a more elegant solution?
Thanks (2 Replies)
Hi,
I have two pipe separated files as below:
head -3 file1.txt
"HD"|"Nov 11 2016 4:08AM"|"0000000018"
"DT"|"240350264"|"56432"
"DT"|"240350264"|"56432"
head -3 file2.txt
"HD"|"Nov 15 2016 2:18AM"|"0000000019"
"DT"|"240350264"|"56432"
"DT"|"240350264"|"56432"
I want to list the... (6 Replies)
Discussion started by: Prasannag87
6 Replies
LEARN ABOUT PHP
dateinterval.format
DATEINTERVAL.FORMAT(3) 1 DATEINTERVAL.FORMAT(3)DateInterval::format - Formats the interval
SYNOPSIS
public string DateInterval::format (string $format)
DESCRIPTION
Formats the interval.
PARAMETERS
o $format
-
The following characters are recognized in the $format parameter string. Each format character must be prefixed by a percent sign (
%).
+------------------+--------------------------------------+---+
|$format character | | |
| | | |
| | Description | |
| | | |
| | Example values | |
| | | |
+------------------+--------------------------------------+---+
| | | |
| % | | |
| | | |
| | Literal % | |
| | | |
| | | |
| | % | |
| | | |
| | | |
| Y | | |
| | | |
| | Years, numeric, at least 2 digits | |
| | with leading 0 | |
| | | |
| | | |
| | 01, 03 | |
| | | |
| | | |
| y | | |
| | | |
| | Years, numeric | |
| | | |
| | | |
| | 1, 3 | |
| | | |
| | | |
| M | | |
| | | |
| | Months, numeric, at least 2 digits | |
| | with leading 0 | |
| | | |
| | | |
| | 01, 03, 12 | |
| | | |
| | | |
| m | | |
| | | |
| | Months, numeric | |
| | | |
| | | |
| | 1, 3, 12 | |
| | | |
| | | |
| D | | |
| | | |
| | Days, numeric, at least 2 digits | |
| | with leading 0 | |
| | | |
| | | |
| | 01, 03, 31 | |
| | | |
| | | |
| d | | |
| | | |
| | Days, numeric | |
| | | |
| | | |
| | 1, 3, 31 | |
| | | |
| | | |
| a | | |
| | | |
| | Total number of days as a result of | |
| | a DateTime::diff or (unknown) other- | |
| | wise | |
| | | |
| | | |
| | 4, 18, 8123 | |
| | | |
| | | |
| H | | |
| | | |
| | Hours, numeric, at least 2 digits | |
| | with leading 0 | |
| | | |
| | | |
| | 01, 03, 23 | |
| | | |
| | | |
| h | | |
| | | |
| | Hours, numeric | |
| | | |
| | | |
| | 1, 3, 23 | |
| | | |
| | | |
| I | | |
| | | |
| | Minutes, numeric, at least 2 digits | |
| | with leading 0 | |
| | | |
| | | |
| | 01, 03, 59 | |
| | | |
| | | |
| i | | |
| | | |
| | Minutes, numeric | |
| | | |
| | | |
| | 1, 3, 59 | |
| | | |
| | | |
| S | | |
| | | |
| | Seconds, numeric, at least 2 digits | |
| | with leading 0 | |
| | | |
| | | |
| | 01, 03, 57 | |
| | | |
| | | |
| s | | |
| | | |
| | Seconds, numeric | |
| | | |
| | | |
| | 1, 3, 57 | |
| | | |
| | | |
| R | | |
| | | |
| | Sign " -" when negative, " +" when | |
| | positive | |
| | | |
| | | |
| | -, + | |
| | | |
| | | |
| r | | |
| | | |
| | Sign " -" when negative, empty when | |
| | positive | |
| | | |
| | | |
| | -, | |
| | | |
+------------------+--------------------------------------+---+
RETURN VALUES
Returns the formatted interval.
NOTES
Note
The DateInterval::format method does not recalculate carry over points in time strings nor in date segments. This is expected
because it is not possible to overflow values like "32 days" which could be interpreted as anything from "1 month and 4 days" to "1
month and 1 day".
EXAMPLES
Example #1
DateInterval example
<?php
$interval = new DateInterval('P2Y4DT6H8M');
echo $interval->format('%d days');
?>
The above example will output:
4 days
Example #2
DateInterval and carry over points
<?php
$interval = new DateInterval('P32D');
echo $interval->format('%d days');
?>
The above example will output:
32 days
Example #3
DateInterval and DateTime::diff with the %a and %d modifiers
<?php
$january = new DateTime('2010-01-01');
$february = new DateTime('2010-02-01');
$interval = $february->diff($january);
// %a will output the total number of days.
echo $interval->format('%a total days')."
";
// While %d will only output the number of days not already covered by the
// month.
echo $interval->format('%m month, %d days');
?>
The above example will output:
31 total days
1 month, 0 days
SEE ALSO
DateTime::diff.
PHP Documentation Group DATEINTERVAL.FORMAT(3)