does anybody know how to find out the number of
days elapsed between 2 dates
e.g.
days elapsed between 020212 and 020110 (YYMMDD format)
Thanking you in advance.
Ravi. (1 Reply)
Hi All
How to get the difference between two dates in no of days ??? My date format is like this YYYY/MM/DD. I have to get the no of days between two dates in the given format.
I tried to search the forum but nothing came up similar to my requitement. Your help will be appreciated.
... (1 Reply)
Hi All,
Can unix cshell list out the number of days between 070201 and 070205 (format is yymmdd) and list out all the dates in between in similiar format.
set startdate = `date '+%y%m%d'` #eg 070201
set enddate = `date '+%y%m%d'` #eg 070205
i would expect the number of days to be 5... (2 Replies)
Hi
I'm looking for a .ksh script/function that will calculate ONLY the number of days between two distinct dates. Further convert the number of days to weeks and display. I need this to be part of another larger script that checks the password expiry on several servers and notifies the... (1 Reply)
Hello,
I would like to find out the number of days between two dates of the format yyyy-mm-dd.
Any help on this is highly appreciated.
Thanks. (6 Replies)
Hi
I need one single command to get number of days between
two given dates.datecalc is not working.
ex.
fromdate:01.04.2010
todate :24.04.2010
i should get the out put as 23
Thanks in advance (4 Replies)
I have two times in the format of YYMMDD. Does anyone know an easy way in ksh for me to display how many days are between the two dates?
Example1:
X=101202
Y=101205
There are 3 days between X & Y
Example2:
X=101202
Y=111202
There are 365 days between X & Y
Example3:
X=101205... (3 Replies)
I wrote the day calculator also in bash. I would like to now, that is it good so?
#!/bin/bash
datum1=`date -d "1991/1/1" "+%s"`
datum2=`date "+%s"`
diff=$(($datum2-$datum1))
days=$(($diff/(60*60*24)))
echo $days
Thanks in advance for your help! (3 Replies)
Hi Am using Unix Ksh
I have a two date input as
DATE1=02/12/2012
DATE2=30/12/2012
I Need the output as only sunday date
02/12/2012
09/12/2012
16/12/2012
23/12/2012
30/12/2012
can anyone pls help me..
thanks in advance... (2 Replies)
Discussion started by: Venkatesh1
2 Replies
LEARN ABOUT LINUX
dp
DP(8) [nmh-1.5] DP(8)NAME
dp - parse dates 822-style
SYNOPSIS
/usr/lib/mh/dp [-form formatfile] [-format string] [-width columns] [-version] [-help] dates ...
DESCRIPTION
Dp is a program that parses dates according to the ARPA Internet standard. It also understands many non-standard formats, such as those
produced by TOPS-20 sites and some UNIX sites using ctime(3). It is useful for seeing how nmh will interpret a date.
The dp program treats each argument as a single date, and prints the date out in the official 822-format. Hence, it is usually best to
enclose each argument in quotes for the shell.
To override the output format used by dp, the -format string or -format file switches are used. This permits individual fields of the
address to be extracted with ease. The string is simply a format string and the file is simply a format file. See mh-format(5) for the
details.
Here is the default format string used by dp:
%<(nodate{text})error: %{text}%|%(putstr(pretty{text}))%>
which says that if an error was detected, print the error, a `:', and the date in error. Otherwise, output the 822-proper format of the
date.
FILES
$HOME/.mh_profile The user profile
PROFILE COMPONENTS
None
SEE ALSO ap(8), Standard for the Format of ARPA Internet Text Messages (RFC-822)
DEFAULTS
`-format' default as described above
`-width' default to the width of the terminal
CONTEXT
None
BUGS
The argument to the -format switch must be interpreted as a single token by the shell that invokes dp. Therefore, one must usually place
the argument to this switch inside quotes.
MH.6.8 11 June 2012 DP(8)