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Full Discussion: Error when executing script
Operating Systems Linux Red Hat Error when executing script Post 302996996 by anaigini45 on Friday 5th of May 2017 06:32:14 AM
Old 05-05-2017
I don't know if the method I am using is complex, but the aim of this script is to generate reports every 1st, 7th and 15th of every month. However, the reports won't be generated until a few days after these dates. Like the reports for the 1st will be generated on the 5th of the month for example. And reports for the 7th will be generated on the 9th or 10th. And reports for the 15th will be generated on the 17th. These days of course will have to fall on a weekday, and not a weekend, which is why we cannot put a fixed date, for each batch.

For the reports on the 1st, I have to copy files dated 2nd onwards from the main directory that it was generated in, into another directory.
This is why I am cracking my head on how to get this done.

For example, these are the files listed in the main directory :

Code:
-rw-r-----  1 Debian-exim adm  1705192 May  1 06:25 mainlog.5.gz
-rw-r-----  1 Debian-exim adm 16737648 May  2 06:25 mainlog.4.gz
-rw-r-----  1 Debian-exim adm 11031310 May  3 06:33 mainlog.3.gz
-rw-r-----  1 Debian-exim adm  8258806 May  4 06:28 mainlog.2.gz
-rw-r-----  1 Debian-exim adm 37434708 May  5 06:26 mainlog.1
-rw-r-----  1 Debian-exim adm 14248899 May  5 17:43 mainlog
root@L28mustang:/var/log/exim4#

I have to copy these files, as you can see, dated May 2nd onwards till the latest (in this case, the 5th) to another directory. How do I create a bash script to do this? These are however not the only files here. There are older files from previous months also here. I need to copy over only the latest months' files dated 2nd onwards to another directory. The script has to be intelligent enough to recognize the files needed for that particular batch (1st, 7th, or 15th), and copy it over to another directory.

Then once it has been copied over to the other directory, this command has to be executed :

Code:
exigrep L28stream1 mainlog.2.gz | egrep -v "jiun.shyong.hor@ericsson.com|chander.c.shekher@ericsson.com|nagios|L28eagle" > mainlog.2.filtered

Means the oldest mainlog file will be labelled with the higher number. In the example above, the date of the oldest file was 16th (this was for batch 15). The report was generated on the 17th. Therefore the name of the oldest mainlog file will be "mainlog.2". Then there were 2 mainlog files generated on the 17th, which was mainlog.1 and mainlog.

This is the script that I have created so far. Any corrections and additional advise will definitely be very appreciated :

Code:
#!/bin/bash

DAY=$(date + %d)
MONTH=$(date +%b)
YEAR=$(date +%Y)
BC01="Blast_BC01"
BC15="Blast_BC15"
DIR1=$MONTH$YEAR_$BC01
DIR2=$MONTH$YEAR_$BC15
FOLDER=$YEAR

DIGMON=$(date +%m)

D=$(stat -c %z mainlog.* | awk -F"[ -]" '{print $3}')
FDAY=$(date -d "$D" '+%d')
FMON=$(date -d "$D" '+%m')
FYEAR=$(date -d "$D" '+%Y')

FILEDATE=$YEAR"-"$DIGMON"-"$i

cd /var/log/exim4

if [ ! -d "$YEAR" ]; then
    mkdir $YEAR
        if [ $DAY < 15 ];then
            mkdir -p /var/log/exim4/$YEAR/$DIR1
            for (( $D=2; $D<=$DAY; $D++ ))
                cp -p mainlog* ./$YEAR/$DIR1
            
        else
            mkdir -p /var/log/exim4/$YEAR/$DIR2
            for (( $D=16; $D<=$DAY; $D++ ))
                cp -p mainlog* ./$YEAR/$DIR2
        fi
else
    cd $FOLDER
        if [ $DAY < 15 ];then
            mkdir -p /var/log/exim4/$YEAR/$DIR1
            for ($D=2; $D<$DAY; $D++)
                cp -p mainlog* ./$YEAR/$DIR1
                    cd /$YEAR/$DIR1
                    count=$(ls -lrt | wc -l)
                    for (i=;i<=$count;i++)
                    exigrep L28stream1 mainlog.$count.gz | egrep -v "jiun.shyong.hor@ericsson.com|chander.c.shekher@ericsson.com|nagios|L28eagle" > mainlog.$count.filtered
            
        else
            mkdir -p /var/log/exim4/$YEAR/$DIR2
            for ($D=16; $D<$DAY; $D++)
                cp -p mainlog* ./$YEAR/$DIR2
        fi
fi

---------- Post updated at 06:32 PM ---------- Previous update was at 06:18 PM ----------

For TESTING purposes ONLY, however, I tried running some commands from the terminal to copy files from the directory /home/emokheng to /home/emoaigin :

These are the files in /home/emokheng :

Code:
[root@L28tstream1 emokheng]# ls -lrt
total 8
-rw-rw-r-- 1 emokheng emokheng 328 Aug 18  2015 foreign.pl
-rw-rw-r-- 1 emokheng emokheng  91 Aug 18  2015 afterinstallforeign.pl

As you can see the dates of the files are August 18th. For report generation this will be considered batch 15. These are the steps I have performed :

Code:
[root@L28tstream1 emokheng]# D="$(stat -c %z * | awk -F"[ -]" '{print $3}')"
[root@L28tstream1 emokheng]# echo "$D"
18
18
[root@L28tstream1 emokheng]# for (( "$D"=16; "$D"<=20; "$D"++ ));
> do
> cp -r * /home/emoaigin/
> done
-bash: ((: 18
18=16: syntax error in expression (error token is "18=16")
[root@L28tstream1 emokheng]#

What is wrong in these steps? Why does it not recognize files dated 18th and copy it over?
 

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