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Full Discussion: Simple awk command to compare two files and print first difference
Top Forums Shell Programming and Scripting Simple awk command to compare two files and print first difference Post 302996501 by LMHmedchem on Wednesday 26th of April 2017 09:10:01 PM
Old 04-26-2017
In the end, I did this based on the code posted by Scrutinizer,

error_record=$(awk '{getline s<f} $0!=s{print; exit}' f=file2 file1)

It seems like it will work well enough and was the fastest of the methods that worked.

This suggestion of RudiC also worked but was marginally slower.

error_record=$(diff -y -b --suppress-common-lines file1 file2 | cut -f1 | head -1)

By slower I mean 0m0.391s as opposed to 0m0.156s with the first method. Not enough difference to bother with but I guess you need some reason to pick a method.

The method suggested by rdrtx1 also worked but again was a bit slower,

error_record=$(paste -d" " file1 file2 | awk '$1 != $2 {print $1; exit;}')

My guess is that the two slower methods both made calls to more than one program and this is the origin of the difference.

I was not able to get any output from this, even though it looks correct,

awk ' NR==FNR { a[NR]=$0; next } $0 != a[FNR] { print a[FNR]; exit }' file1 file2

Don't know what the issue is there.

LMHmedchem
Last edited by LMHmedchem; 04-26-2017 at 10:15 PM..
This User Gave Thanks to LMHmedchem For This Post:
Scrutinizer
 

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set_color(1)							       fish							      set_color(1)

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